c - C中使用循环读取所有文本文件

Question

我知道我们有很多不同的方法来实现一个功能。有人有想法使用循环案例一次读取所有文本文件吗？

int readTenFiles(char (*names)[MAX_LENGTH_NAME], int (*ranks)[YEAR], int namesCount) {
    int yearIndex = 0;
    namesCount = readOneFile(fopen("yob1920.txt", "r"), names, ranks, yearIndex++, namesCount);
    namesCount = readOneFile(fopen("yob1930.txt", "r"), names, ranks, yearIndex++, namesCount);
    namesCount = readOneFile(fopen("yob1940.txt", "r"), names, ranks, yearIndex++, namesCount);
    namesCount = readOneFile(fopen("yob1950.txt", "r"), names, ranks, yearIndex++, namesCount);
    namesCount = readOneFile(fopen("yob1960.txt", "r"), names, ranks, yearIndex++, namesCount);
    namesCount = readOneFile(fopen("yob1970.txt", "r"), names, ranks, yearIndex++, namesCount);
    namesCount = readOneFile(fopen("yob1980.txt", "r"), names, ranks, yearIndex++, namesCount);
    namesCount = readOneFile(fopen("yob1990.txt", "r"), names, ranks, yearIndex++, namesCount);
    namesCount = readOneFile(fopen("yob2000.txt", "r"), names, ranks, yearIndex++, namesCount);
    return readOneFile(fopen("yob2010.txt", "r"), names, ranks, yearIndex++, namesCount);
}

Answer 1

在一个数组中分配文件名列表，然后在这个数组上循环。

char *filenames[] = { 
    "yob1920.txt" ,
    "yob1930.txt" ,
    "yob1940.txt" ,
    "yob1950.txt" ,
    "yob1960.txt" ,
    "yob1970.txt" ,
    "yob1980.txt" ,
    "yob1990.txt" ,
    "yob2000.txt" ,
    "yob2010.txt" ,
};
int i = 0;
for ( i=0; i<sizeof(filenames)/sizeof(*filenames); i++ ) { 
    namesCount = readOneFile(fopen(filenames[i], "r"), names, ranks, yearIndex++, namesCount);
}