python - 如何按字母数字顺序设置列表？

Question

我有一个包含 10 个子文件夹的文件夹，其命名如下:

文件夹 1、文件夹 2、文件夹 3、...我想按那个顺序操纵它们，但是当我申请时

lst = os.listdir(dirname)
lst.sort()

输出如下:

Folder1
Folder10
Folder2
Folder3
Folder4
Folder5
Folder6
Folder7
Folder8
Folder9

这是预期的，为了正确地解决问题，我做了以下事情:

lst = os.listdir(dirname)
lst.sort()

projects = {}

for p in lst:
    pInt = re.sub(r"Folder", " ", p)
    projects[pInt] = p
    print(p)

print projects

得到以下结果:

{' 10': 'Folder10', ' 2': 'Folder2', ' 3': 'Folder3', ' 1': 'Folder1', ' 6': 'Folder6', ' 7': 'Folder7', ' 4': 'Folder4', ' 5': 'Folder5', ' 8': 'Folder8', ' 9': 'Folder9'}

我如何从那里继续正确列出它们，以便我的系统将按顺序逐一访问它们

Answer 1

您可以使用带有自定义键的sorted。默认的顺序是字典顺序，这对您的目的不起作用。

>>> data
['Folder1', 'Folder10', 'Folder2', 'Folder3', 'Folder4', 'Folder5', 'Folder6', 'Folder7', 'Folder8', 'Folder9']
>>> sorted(data)
['Folder1', 'Folder10', 'Folder2', 'Folder3', 'Folder4', 'Folder5', 'Folder6', 'Folder7', 'Folder8', 'Folder9']
>>> sorted(data, key= lambda s: int(s.replace('Folder', '')))
['Folder1', 'Folder2', 'Folder3', 'Folder4', 'Folder5', 'Folder6', 'Folder7', 'Folder8', 'Folder9', 'Folder10']

如果不是每个文件夹都称为 FolderX，您可以使用此键:

>>> sorted(data, key= lambda s: int(''.join(filter(str.isdigit, s))))
['Folder1', 'Folder2', 'Data3', 'Folder4', 'Folder5', 'Folder6', 'Folder7', 'Folder8', 'Folder9', 'Folder10']

另一种方法是将您的 folderX 重命名为 folder0X。 Folder02 将排在 Folder10 之前。