python - 如何在列表中构建字典数据？

Question

我有这个程序:

def file(fname):
    lines = open(fname).read().splitlines()
    return(lines)
print(file('venue.txt'))

结果是这样的，我把它改成了列表:

['room 1,  10,  250']

我如何用它建立字典数据，以便它可以像这样:

[{'name': 'room 1', 'max': 10, 'cost': 250}]

一些线索也许可以帮助我构建它。谢谢

编辑:

def file(fname):
    lines = open(fname).read().splitlines()
    new = []
    for i in lines:
        split = i.split(', ')
        new.append({'name':split[0],'max':split[1],'cost':split[2]})
    return(new)   
print(file('venue.txt'))

它打印:

new.append({'name':split[0],'max':split[1],'cost':split[2]})
IndexError: list index out of range

这是什么意思？

Answer 1

你可以试试这个:

import re
def file(fname):
   lines = open(fname).read().splitlines()
   return(lines)
headers = ["name", "max", "cost"]
data1 = [re.split(",\s+", i) for i in file("venue.txt")]
final_data = [{a:b for a, b in zip(headers, data} for data in data1]
print(final_data)