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python - 函数中的 exec 函数不起作用(python 3.5)

转载 作者:太空宇宙 更新时间:2023-11-04 02:40:12 24 4
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我正在尝试在 python 中编写一个动态程序(根据标签解析 json 文件),我正在使用 Python exec 函数来执行此操作。但是当 exec 语句在函数中时程序失败。

运行 1:在函数中执行:

import json
from pandas.io.json import json_normalize
import sys
def param(dfile):
aString = "['widget']['image']~['widget']['window']~['widget']['text']"
for nd_part in aString.split('~'):
exec("temp = %s%s"%(dfile,nd_part))
print(temp)
if __name__ == "__main__":
dfile = json.load(open("sample_json.json"))
str_list = param(dfile)

JSON 数据:sample_json.json

{"widget": {
"debug": "on",
"window": {
"title": "Sample Konfabulator Widget",
"name": "main_window",
"width": 500,
"height": 500
},
"image": {
"src": "Images/Sun.png",
"name": "sun1",
"hOffset": 250,
"vOffset": 250,
"alignment": "center"
},
"text": {
"data": "Click Here",
"size": 36,
"style": "bold",
"name": "text1",
"hOffset": 250,
"vOffset": 100,
"alignment": "center",
"onMouseUp": "sun1.opacity = (sun1.opacity / 100) * 90;"
}
}}

错误:

Traceback (most recent call last):
File "sample_test_json.py", line 12, in <module>
str_list = param(dfile)
File "sample_test_json.py", line 9, in param
print(temp)
NameError: name 'temp' is not defined

运行 2:主要执行:

import json
from pandas.io.json import json_normalize
import sys
if __name__ == "__main__":
dfile = json.load(open("sample_json.json"))
aString = "['widget']['image']~['widget']['window']~['widget']['text']"
for nd_part in aString.split('~'):
exec("temp = %s%s"%(dfile,nd_part))
print(temp)

JSON数据:sample_json.json(同上数据)

输出:没有错误(结果符合预期)

{'hOffset': 250, 'vOffset': 250, 'name': 'sun1', 'alignment': 'center', 'src': 'Images/Sun.png'}
{'width': 500, 'height': 500, 'name': 'main_window', 'title': 'Sample Konfabulator Widget'}
{'data': 'Click Here', 'hOffset': 250, 'vOffset': 100, 'size': 36, 'style': 'bold', 'onMouseUp': 'sun1.opacity = (sun1.opacity / 100) * 90;', 'name': 'text1', 'alignment': 'center'}

运行 3:我尝试了 eval 并尝试格式化这篇文章中的字符串。 How to return value from exec in function?

import json
from pandas.io.json import json_normalize
import sys
def param(dfile):
aString = "['widget']['image']~['widget']['window']~['widget']['text']"
for nd_part in aString.split('~'):
exec('temp = "{}""{}"'.format(dfile,nd_part))
print(temp)
if __name__ == "__main__":
dfile = json.load(open("sample_json.json"))
str_list = param(dfile)

错误:

Traceback (most recent call last):
File "sample_test_json.py", line 12, in <module>
str_list = param(dfile)
File "sample_test_json.py", line 9, in param
print(temp)
NameError: name 'temp' is not defined

请帮助我确定问题所在。提前致谢。

最佳答案

使用 Eval() 我得到了我期望的结果。在下面发布答案。但我仍然不确定为什么 exec() 不起作用。

import json
from pandas.io.json import json_normalize
import sys
def param(dfile):
aString = "['widget']['image']~['widget']['window']~['widget']['text']"
for nd_part in aString.split('~'):
s = '{0}{1}'.format('dfile',nd_part)
temp = eval(s)
print(temp)
if __name__ == "__main__":
dfile = json.load(open("sample_json.json"))
str_list = param(dfile)

结果:

{'src': 'Images/Sun.png', 'alignment': 'center', 'vOffset': 250, 'name': 'sun1', 'hOffset': 250}
{'title': 'Sample Konfabulator Widget', 'height': 500, 'width': 500, 'name': 'main_window'}
{'alignment': 'center', 'onMouseUp': 'sun1.opacity = (sun1.opacity / 100) * 90;', 'data': 'Click Here', 'hOffset': 250, 'size': 36, 'vOffset': 100, 'name': 'text1', 'style': 'bold'}

关于python - 函数中的 exec 函数不起作用(python 3.5),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46774217/

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