python - 从文件python创建字典

Question

我是 python 的新手，我正在尝试读取一个文件并从中创建一个字典。格式如下:

.1.3.6.1.4.1.14823.1.1.27 {
    TYPE = Switch
    VENDOR = Aruba
    MODEL = ArubaS3500-48T
    CERTIFICATION = CERTIFIED
    CONT = Aruba-Switch
    HEALTH = ARUBA-Controller
    VLAN = Dot1q    INSTRUMENTATION:
     Card-Fault            = ArubaController:DeviceID
     CPU/Memory            = ArubaController:DeviceID
     Environment              = ArubaSysExt:DeviceID
     Interface-Fault       = MIB2
     Interface-Performance = MIB2
     Port-Fault            = MIB2
     Port-Performance      = MIB2 
}

第一行 OID (.1.3.6.1.4.1.14823.1.1.27 { ) 我希望这是键，其余行是值，直到

我尝试了一些组合，但无法获得正确的正则表达式来匹配这些组合

有什么帮助吗？

我试过类似的东西

lines = cache.readlines()

for line in lines:

    searchObj = re.search(r'(^.\d.*{)(.*)$', line)

    if searchObj:
        (oid, cert ) = searchObj.groups()

    results[searchObj(oid)] = ", ".join(line[1:])

    print("searchObj.group() : ", searchObj.group(1))

    print("searchObj.group(1) : ", searchObj.group(2))

Answer 1

你可以试试这个:

import re
data = open('filename.txt').read()
the_key = re.findall("^\n*[\.\d]+", data)
values = [re.split("\s+\=\s+", i) for i in re.findall("[a-zA-Z0-9]+\s*\=\s*[a-zA-Z0-9]+", data)]
final_data = {the_key[0]:dict(values)}

输出:

{'\n.1.3.6.1.4.1.14823.1.1.27': {'VENDOR': 'Aruba', 'CERTIFICATION': 'CERTIFIED', 'Fault': 'MIB2', 'VLAN': 'Dot1q', 'Environment': 'ArubaSysExt', 'HEALTH': 'ARUBA', 'Memory': 'ArubaController', 'Performance': 'MIB2', 'CONT': 'Aruba', 'MODEL': 'ArubaS3500', 'TYPE': 'Switch'}}