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c - 三个进程的信号量

转载 作者:太空宇宙 更新时间:2023-11-04 02:37:15 24 4
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一个内存位置由三个进程共享。每个进程独立地尝试将共享内存位置的内容从 1 增加到某个值,增量为 1。进程1的目标是100000,进程2的目标是200000,进程3的目标是300000。因此,当程序终止时,共享内存变量总共有600000(即这个值将由三个进程中的任何一个输出)最后完成)。我要使用信号量保护临界区。 我的问题是初始化信号量时每个进程的 SETVAL 都有问题。即使我将其设置为 1,它仍会继续打印“在 SETVAL 中检测到错误”。正确的示例输出以及我的代码如下所示:

Sample output 

From Process 1: counter = 100000.
From Process 2: counter = 300000.
From Process 3: counter = 600000.

Child with ID 2412 has just exited.
Child with ID 2411 has just exited.
Child with ID 2413 has just exited.

End of Simulation.



/*ass1*/

#include <stdio.h>
#include <sys/types.h>
#include <sys/ipc.h>
#include <sys/shm.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/sem.h>

#define SEMKEY ((key_t) 400L)
// number of semaphores being created
#define NSEMS 2

/* change the key number */
#define SHMKEY ((key_t) 7890)


typedef struct
{
int value;
} shared_mem;

shared_mem *total;

//structure
int sem_id, sem_id2;

typedef union{
int val;
struct semid_ds *buf;
ushort *array;
} semunion;

static struct sembuf OP = {0,-1,0};
static struct sembuf OV = {0,1,0};
struct sembuf *P =&OP;
struct sembuf *V =&OV;
//function
int Pop()
{
int status;
status = semop(sem_id, P,1);
return status;
}
int Vop()
{
int status;
status = semop(sem_id, V,1);
return status;
}




/*----------------------------------------------------------------------*
* This function increases the value of shared variable "total"
* by one with target of 100000
*----------------------------------------------------------------------*/

void process1 ()
{
int k = 0;

while (k < 100000)
{


Pop();
if (total->value < 600000) {
total->value = total->value + 1;
}

Vop();
k++;

}


printf ("From process1 total = %d\n", total->value);

}


/*----------------------------------------------------------------------*
* This function increases the vlaue of shared memory variable "total"
* by one with a target 200000
*----------------------------------------------------------------------*/

void process2 ()
{
int k = 0;

while (k < 200000)
{


Pop();
if (total->value < 600000) {
total->value = total->value + 1;
}

Vop();
k++;
}

printf ("From process2 total = %d\n", total->value);

}

/*----------------------------------------------------------------------*
* This function increases the vlaue of shared memory variable "total"
* by one with a target 300000
*----------------------------------------------------------------------*/
void process3 ()
{
int k = 0;

while (k < 300000)
{


Pop();
if (total->value < 600000) {
total->value = total->value + 1;
}

Vop();
k++;
}

printf ("From process3 total = %d\n", total->value);

}


/*----------------------------------------------------------------------*
* MAIN()
*----------------------------------------------------------------------*/

int main()
{
int shmid;
int pid1;
int pid2;
int pid3;
int ID;
int status;


char *shmadd;
shmadd = (char *) 0;

//semaphores
int semnum = 0;
int value, value1;
semunion semctl_arg;
semctl_arg.val =1;

/* Create semaphores */
sem_id = semget(SEMKEY, NSEMS, IPC_CREAT | 0666);
if(sem_id < 0)
printf("creating semaphore");

sem_id2 = semget(SEMKEY, NSEMS, IPC_CREAT | 0666);
if(sem_id2 < 0)
printf("creating semaphore");

/* Initialize semaphore */
value1 =semctl(sem_id, semnum, SETVAL, semctl_arg);

value =semctl(sem_id, semnum, GETVAL, semctl_arg);
if (value < 1)
printf("Eror detected in SETVAL");




/* Create and connect to a shared memory segmentt*/

if ((shmid = shmget (SHMKEY, sizeof(int), IPC_CREAT | 0666)) < 0)
{
perror ("shmget");
exit (1);
}


if ((total = (shared_mem *) shmat (shmid, shmadd, 0)) == (shared_mem *) -1)
{
perror ("shmat");
exit (0);
}


total->value = 0;

if ((pid1 = fork()) == 0)
process1();

if ((pid1 != 0) && (pid2 = fork()) == 0)
process2();

if ((pid1 != 0 ) && (pid2 != 0) && (pid3 = fork()) == 0 )
process3();


waitpid(pid1, NULL, 0 );
waitpid(pid2, NULL, 0 );
waitpid(pid3, NULL, 0 );

if ((pid1 != 0) && (pid2 != 0) && (pid3 != 0))
{
waitpid(pid1);
printf("Child with ID %d has just exited.\n", pid1);

waitpid(pid2);
printf("Child with ID %d has just exited.\n", pid2);

waitpid(pid3);
printf("Child with ID %d has just exited.\n", pid3);

if ((shmctl (shmid, IPC_RMID, (struct shmid_ds *) 0)) == -1)
{
perror ("shmctl");
exit (-1);
}

printf ("\t\t End of Program\n");

/* De-allocate semaphore */
semctl_arg.val = 0;
status =semctl(sem_id, 0, IPC_RMID, semctl_arg);
if( status < 0)
printf("Error in removing the semaphore.\n");
}

}

最佳答案

一些基础知识 - IPC 比进程持续时间更长,因此如前所述,使用 ipcsipcrm 删除运行之间预先存在的 ipc。确保在执行后删除 ipcs

waitpid(pid1, NULL, 0 );
waitpid(pid2, NULL, 0 );
waitpid(pid3, NULL, 0 );

这个部分是为 children 准备的——他们可能不应该。

  total->value = total->value + 1;

不是 IPC 安全的,所以可能会出现不同的结果(proc1 可能会覆盖 proc2 的增量)。

关于c - 三个进程的信号量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35852738/

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