python - 写入 yaml 文件 : attribute error

Question

我正在尝试读取一个 yaml 文件，替换它的一部分并将结果写入同一个文件，但是我得到一个属性错误。

代码

import yaml
import glob
import re
from yaml import load, dump
from yaml import CLoader as Loader, CDumper as Dumper
import io

list_paths = glob.glob("my_path/*.yaml")

for path in list_paths:    
    with open(path, 'r') as stream:
        try:
            text = load(stream, Loader=Loader)
            text = str(text)
            print text
            if "my_string" in text:
                start = "'my_string': '"
                end = "'"
                m = re.compile(r'%s.*?%s' % (start,end),re.S)
                m = m.search(text).group(0)
                text[m] = "'my_string': 'this is my string'"  
        except yaml.YAMLError as exc:
            print(exc)
    with io.open(path, 'w', encoding = 'utf8') as outfile:
        yaml.dump(text, path, default_flow_style=False, allow_unicode=True)

错误我在 yaml_dump 行

收到此错误

AttributeError: 'str' object has no attribute 'write' 

到目前为止我尝试了什么

• 没有将文本转换为字符串，但随后我在 m.search 行收到错误:

  TypeError:预期的字符串或缓冲区

• 首先转换为字符串，然后再次转换为 dict，但是我从代码 text: dict(text) 得到这个错误:ValueError:字典更新序列元素 #0 的长度为 1； 2 是必需的

Yaml 文件

my string: something
string2: something else

预期结果:yaml 文件

my string: this is my string
string2: something else

Answer 1

要停止出现该错误，您需要做的就是更改

with io.open(path, 'w', encoding = 'utf8') as outfile:
    yaml.dump(text, path, default_flow_style=False, allow_unicode=True)

到

with open(path, 'w') as outfile:
    yaml.dump(text.encode("UTF-8"), outfile, default_flow_style=False, allow_unicode=True)

正如其他答案所说，此解决方案只是将字符串 path 替换为打开的文件描述符。