python - 使用多处理搜索列表

Question

下面是一个示例代码，它检查列表中是否存在某个项目并将其写入另一个 a 列表:

list_1 = [(0,1),(3,2),(1,5),(0,3),(3,7)]

a = []
for i in list_1:
    if i[0]==3:
       a.append(i)
       break

输出:

[(3, 2)]

当找到第一个满足条件的元素时，循环结束。

假设列表 list_1 非常大，如何在这种情况下应用多处理？

Answer 1

Brake your big list into smaller lists
>>> big= [(0,1),(3,2),(1,5),(0,3),(3,7)]
>>> a=big[0:2]
>>> b=big[2:]
define a function to look for your tuple and return it or return None
>>> def doit(L):
        for i in L:
            if i[0]==3:
                return i
        return None
figure out how to create a new process and call it with each of the smaller lists
>>> doit(a)
(3, 2)
>>> doit(b)
(3, 7)
look at the tuples returned that are not None in order and choose the first one