c - 在 C 中使用函数填充的指向结构的指针数组

Question

我正在尝试编写一个程序来填充指向结构的指针数组，但使用一个函数来执行此操作。我相信我对指针做错了什么，因为我需要在 add() 的末尾保留 b1 的地址；程序可以编译，但出现运行时错误。

这是我的代码:

#include <stdio.h>
#include <stdlib.h>

char *title[]= {"a", "b", "c"};
int bookNum[]= {1, 2, 3};

typedef struct
{
  char *BookName;
  int BookNumber;
}Book;

static void add(Book *b1, char *book, int num)
{
  static int count = 0;
  /*trying to create new book struct and give the right address*/
  Book *b2 = (Book*) malloc (sizeof(Book));
  b2 = b1;

  b2->BookName = book;
  b2->BookNumber = num;
  count++
}

int main(int argc, char **argv)
{
  Book *books[3];

  for  (int i = 0; i < 3; i++)
    add(books[i], title[i], bookNum[i]);    


  for (int i = 0; i < 3; i++)
    printf("Name: %s --- Age: %i \n", books[i]->BookName, books[i]->BookNumber);

  return 0;
}

Answer 1

你非常接近:你需要将指针传递给指针，然后反转赋值:

static void add(Book **b1, char *book, int num) // Take pointer to pointer
{
  static int count = 0;
  /*trying to create new book struct and give the right address*/
  Book *b2 = malloc (sizeof(Book)); // Don't cast malloc, C lets you do it
  *b1 = b2; // <<== Assign to what's pointed to by b1, not to b2

  b2->BookName = book;
  b2->BookNumber = num;
  count++
}

对 add() 的调用应该如下所示:

add(&books[i], title[i], bookNum[i]);    
//  ^
//  |
// Pass the address of the pointer