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python - urlopen 不适用于特定的 url

转载 作者:太空宇宙 更新时间:2023-11-04 02:29:01 24 4
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大家好,我是编程的新手,所以请原谅我的任何新手错误。我试图在 python 3.6 中使用 urllib 来查找网页上的字符串和我找到的解决方案 here适用于我测试过的大多数网页,例如:

from urllib.request import urlopen
>>>string = 'google'
>>>url = 'https://google.com/'
>>>webp=urlopen(url).read()
>>>isfound = webp.find(string.encode('utf-8'))
>>>print(isfound)
186

但是当我尝试使用 URL https://chan.sankakucomplex.com/ 时(NSFW) 我遇到了很多错误,但我不知道为什么。我已经尝试将我的 DNS 更改为 8.8.8.8,但这并没有改变任何东西。

错误: Traceback (most recent call last):
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 1318, in do_open
encode_chunked=req.has_header('Transfer-encoding'))
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1239, in request
self._send_request(method, url, body, headers, encode_chunked)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1285, in _send_request
self.endheaders(body, encode_chunked=encode_chunked)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1234, in endheaders
self._send_output(message_body, encode_chunked=encode_chunked)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1026, in _send_output
self.send(msg)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 964, in send
self.connect()
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1392, in connect
super().connect()
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 936, in connect
(self.host,self.port), self.timeout, self.source_address)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\socket.py", line 704, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\socket.py", line 743, in getaddrinfo
for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno 11004] getaddrinfo failed
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:/Users/-/Desktop/python/searcher/stackex.py", line 5, in <module>
webp=urlopen(url).read()
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 223, in urlopen
return opener.open(url, data, timeout)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 526, in open
response = self._open(req, data)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 544, in _open
'_open', req)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 504, in _call_chain
result = func(*args)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 1361, in https_open
context=self._context, check_hostname=self._check_hostname)
File "C:\Users\-\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 1320, in do_open
raise URLError(err)
urllib.error.URLError: <urlopen error [Errno 11004] getaddrinfo failed>

最佳答案

urllib.error.URLError: <urlopen error [Errno 11004] getaddrinfo failed>

这告诉我您的 DNS 服务器拒绝将文本地址 (chan.sankakucomplex.com) 转换为 IP 地址。这不是 Python 的问题。

您能否从运行 Python 代码的同一台机器上运行的 Web 浏览器访问该站点?

关于python - urlopen 不适用于特定的 url,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49671679/

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