c - 运行时指针变化

Question

我有以下文件test.c:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>

#define LEXER_INC(l) ( (l)->pos++ )

#define isCidstart(c) (isalpha(c) || (c)=='_')
#define isCident(c) (isalnum(c) || (c)=='_')

typedef struct LexerState
{
    const char *fileName;
    const char *sourceText;
    int sourceLength;
    const char *pos;
    const char *end;
    int line;
} LexerState;

typedef enum LexerToken
{
    TokenHalt,
    TokenPush,
    TokenPop,
    TokenEndOfLine,
    TokenEOF,
    TokenNone
} LexerToken;

typedef struct ReservedWord
{
    const char *word;
    LexerToken token;
} ReservedWord;

static ReservedWord reservedWords[] =
{
    {"halt", TokenHalt},
    {"push", TokenPush},
    {"pop", TokenPop}
};

void lexerInit(LexerState *lexer)
{
    lexer->fileName = "test.s";
    lexer->sourceText = "pop\r\npush\r\nhalt\r\n"; // read from file
    lexer->sourceLength = strlen(lexer->sourceText); // 17
    lexer->pos = lexer->sourceText; // pointing to first char of lexer->sourceText
    lexer->end = lexer->sourceText + lexer->sourceLength; // end of lexer->sourceText string, i.e. '\0'
    lexer->line = 1;
}

LexerToken lexerCheckReservedWord(const char *word)
{
    for (int count = 0; count < (sizeof(reservedWords) / sizeof(ReservedWord)); count++)
    {
        if (!strcmp(word, reservedWords[count].word))
            return reservedWords[count].token;
    }

    return TokenNone;
}

LexerToken lexerGetWord(LexerState *lexer)
{
    const char *startPos = lexer->pos;
    LexerToken token = TokenNone;
    char *word;
    int len;

    do
    {
        LEXER_INC(lexer);
    }
    while (lexer->pos != lexer->end && isCident(*lexer->pos));

    len = lexer->pos - startPos;
    word = malloc(len + 1); /* (len + 1) for '\0' ending */
    strncpy(word, startPos, len);
    word[len] = '\0';

    token = lexerCheckReservedWord(word);

    return token;
}

LexerToken lexerGetToken(LexerState *lexer)
{
    char thisChar;

    /* Skip white characters */
    while (lexer->pos != lexer->end && isspace(*lexer->pos))
    {
        if (*lexer->pos == '\n')
        {
            /* New line found */
            lexer->line++;
            LEXER_INC(lexer);
            return TokenEndOfLine;
        }

        LEXER_INC(lexer);
    }

    if (lexer->pos == lexer->end || *lexer->pos == '\0')
    {
        return TokenEOF;
    }

    thisChar = *lexer->pos;

    if (isCidstart(thisChar))
    {
        return lexerGetWord(lexer);
    }

    return TokenEOF;
}

int main(int argc, const char *argv[])
{
    LexerState *lexer;
    LexerToken token;

    lexer = malloc(sizeof(lexer));
    lexerInit(lexer);

    while ((token = lexerGetToken(lexer)) != TokenEOF)
    {
        printf("token %d\n", token);
    }

    return EXIT_SUCCESS;
}

当使用 gdb 调试函数 lexerGetWord 时，我意识到在执行 word = malloc((len + 1) * sizeof(char)) 行之后;，lexer->pos 指针地址更改为某个数字(在我的例子中为 0x23):

82              len = lexer->pos - startPos;
(gdb) next
83              word = malloc(len + 1);   // (len + 1) for '\0' ending
(gdb) print len
$1 = 3
(gdb) print lexer->pos
$2 = 0x60003b1b3 "\r\npush\r\nhalt\r\n"

这里lexer->pos从字符串lexer->sourceText中得到单词"pop"后指向这个地址( "pop\r\npush\r\nhalt\r\n")

(gdb) next
84              strncpy(word, startPos, len);
(gdb) print lexer->pos
$3 = 0x23 <error: Cannot access memory at address 0x23>

但是在执行malloc之后，指针改变了它的地址，导致后来Segmentation fault。

$ gcc test.c -o test
$ ./test
token 2
Segmentation fault (core dumped)

我做错了什么？

编辑

这只发生在 Cygwin gcc 中。我尝试了 MinGW，一切正常。

$ uname -a
CYGWIN_NT-6.3 Stepan 2.9.0(0.318/5/3) 2017-09-12 10:18 x86_64 Cygwin

Answer 1

问题出在 main 中:

lexer = malloc(sizeof(lexer));

您正在为指针 分配足够的空间，而不是它指向的内容。结果，您最终写入了已分配内存的末尾。这会调用 undefined behavior .

lexer 指向的内容需要空间:

lexer = malloc(sizeof(*lexer));