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检查指针是否为 NULL 给出段错误

转载 作者:太空宇宙 更新时间:2023-11-04 02:23:07 24 4
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问题陈述:我们必须删除链表的每个备用节点。eg:原来的列表:1->2->3->4->5 到:1->3->5

完整的问题陈述:https://practice.geeksforgeeks.org/problems/delete-alternate-nodes/1/?ref=self

如您所见,这是一个函数问题,所以我实际上并没有编写完整的代码(只需要完成函数)。这是我正在编写的代码:

void deleteAlt(struct Node *head){
// Code here
struct Node *traverse=head,*alternate=head->next;

if(alternate->next==NULL)
{
head->next=NULL;
return;
}

while(traverse->next!=NULL && alternate->next!=NULL)
{
traverse->next = alternate->next;
traverse = traverse->next;
alternate = traverse->next;
if((alternate->next)==NULL) //presence of this if statement causes segmentation fault
{
traverse->next=NULL;
}
}
}

我在 stackoverflow 上遇到过类似的问题,但他们的代码和目标不同,比如,不初始化指针并比较它。但是,我的问题是不同的。

在节点数为偶数的情况下,alternate 始终为 NULL,因此应该没有初始化问题。

最佳答案

你会

while(traverse->next!=NULL && alternate->next!=NULL)
traverse->next = alternate->next;
traverse = traverse->next;
alternate = traverse->next;
if((alternate->next)==NULL) //presence of this if statement causes segmentation fault

事实上

while(traverse->next!=NULL && alternate->next!=NULL)
traverse = alternate->next;
alternate = traverse->next;
if((alternate->next)==NULL) //presence of this if statement causes segmentation fault

事实上

while(traverse->next!=NULL && alternate->next!=NULL)
alternate = alternate->next->next;
if((alternate->next)==NULL) //presence of this if statement causes segmentation fault

事实上

while(traverse->next!=NULL && alternate->next!=NULL)
if((alternate->next->next->next)==NULL) //presence of this if statement causes segmentation fault

alternate->next->next 为 NULL(未被 while 检查)alternate->next->next->next 导致你的段错误


一个解决方案是:

void deleteAlt(struct Node * head)
{
if (head != NULL) {
while (head->next != NULL) {
Node * d = head->next;

head->next = head->next->next;
free(d);
head = head->next;
}
}
}

一个完整的程序来证明:

#include <stdio.h>
#include <stdlib.h>

typedef struct Node {
int v;
struct Node * next;
} Node;

Node * make(int v, Node * n)
{
Node * r = malloc(sizeof(Node));

r->v = v;
r->next = n;

return r;
}

void pr(Node * l)
{
while (l != NULL) {
printf("%d ", l->v);
l = l->next;
}
putchar('\n');
}

void deleteAlt(struct Node * head)
{
if (head != NULL) {
while (head->next != NULL) {
Node * d = head->next;

head->next = head->next->next;
free(d);
head = head->next;
}
}
}

int main()
{
Node * l = make(1, make(2, make(3, make(4, make(5, NULL)))));

pr(l);
deleteAlt(l);
pr(l);

/* free rest of list */
while (l != NULL) {
Node * n = l->next;

free(l);
l = n;
}
}

编译和执行:

pi@raspberrypi:/tmp $ gcc -pedantc -Wextra l.c
pi@raspberrypi:/tmp $ ./a.out
1 2 3 4 5
1 3 5
pi@raspberrypi:/tmp $

valgrind 下执行以检查内存访问/泄漏

pi@raspberrypi:/tmp $ valgrind ./a.out
==2479== Memcheck, a memory error detector
==2479== Copyright (C) 2002-2017, and GNU GPL'd, by Julian Seward et al.
==2479== Using Valgrind-3.13.0 and LibVEX; rerun with -h for copyright info
==2479== Command: ./a.out
==2479==
1 2 3 4 5
1 3 5
==2479==
==2479== HEAP SUMMARY:
==2479== in use at exit: 0 bytes in 0 blocks
==2479== total heap usage: 6 allocs, 6 frees, 1,064 bytes allocated
==2479==
==2479== All heap blocks were freed -- no leaks are possible
==2479==
==2479== For counts of detected and suppressed errors, rerun with: -v
==2479== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 6 from 3)

(编辑)如果列表的长度可以是偶数,则必须将定义更改为:

void deleteAlt(struct Node * head)
{
while ((head != NULL) && (head->next != NULL)) {
Node * d = head->next;

head->next = head->next->next;
free(d);
head = head->next;
}
}

修改 main 以检查:

int main()
{
{
Node * l = make(1, make(2, make(3, make(4, make(5, NULL)))));

pr(l);
deleteAlt(l);
pr(l);

/* free rest of list */
while (l != NULL) {
Node * n = l->next;

free(l);
l = n;
}
}
{
Node * l = make(1, make(2, make(3, make(4, NULL))));

pr(l);
deleteAlt(l);
pr(l);

/* free rest of list */
while (l != NULL) {
Node * n = l->next;

free(l);
l = n;
}
}
}

编译和执行:

pi@raspberrypi:/tmp $ gcc -pedantic -Wextra l.c
pi@raspberrypi:/tmp $ ./a.out
1 2 3 4 5
1 3 5
1 2 3 4
1 3

valgrind 下:

pi@raspberrypi:/tmp $ valgrind ./a.out
==3450== Memcheck, a memory error detector
==3450== Copyright (C) 2002-2017, and GNU GPL'd, by Julian Seward et al.
==3450== Using Valgrind-3.13.0 and LibVEX; rerun with -h for copyright info
==3450== Command: ./a.out
==3450==
1 2 3 4 5
1 3 5
1 2 3 4
1 3
==3450==
==3450== HEAP SUMMARY:
==3450== in use at exit: 0 bytes in 0 blocks
==3450== total heap usage: 10 allocs, 10 frees, 1,096 bytes allocated
==3450==
==3450== All heap blocks were freed -- no leaks are possible
==3450==
==3450== For counts of detected and suppressed errors, rerun with: -v
==3450== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 6 from 3)

关于检查指针是否为 NULL 给出段错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55016702/

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