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python - 绘制正方形 Cartopy map

转载 作者:太空宇宙 更新时间:2023-11-04 02:22:07 26 4
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我需要使用 Cartopy 绘制方形 map 。我目前为我的 map 使用以下代码:

plt.figure(figsize = (15, 15))

img = cimgt.GoogleTiles()

ax = plt.axes(projection = img.crs)
ax.set_extent((d['longitude'].min() - 0.05, d['longitude'].max() + 0.05,
d['latitude'].min() - 0.05, d['latitude'].max() + 0.05))

ax.add_image(img, 10, interpolation = 'bicubic')

plt.scatter(d['longitude'], d['latitude'], transform = ccrs.PlateCarree(),
c = '#E8175D', s = 14)

这工作正常,除了 map 不是正方形这一事实。相反,它正好适合绘图的 (15, 15) 正方形。

enter image description here

我想在左侧和右侧添加更多 map ,使绘图完全呈正方形而不扭曲。简单地将范围设置为相同的纬度和经度差异并不能完成这项工作,因为纬度和经度覆盖 Google(和大多数其他) map 投影中的不同距离。我还找到了this发布,但据我所知,这里的目的是扭曲 map 。

我希望有人知道如何做到这一点。 Cartopy在这方面似乎不是很直观。

最佳答案

要获得方形范围,您需要在 map 投影坐标中指定它。这涉及到一些坐标变换。这是您需要的代码片段。

# crs of your choice
crg = cimgt.StamenTerrain().crs # or cimgt.GoogleTiles().crs

# set map limits, in degrees
lonmin, lonmax = -22, -15
latmin, latmax = 63, 65

# do coordinate transformation
LL = crg.transform_point(lonmin, latmin, ccrs.Geodetic())
UR = crg.transform_point(lonmax, latmax, ccrs.Geodetic())
EW = UR[0] - LL[0]
SN = UR[1] - LL[1]

# get side of the square extent (in map units, usually meters)
side = max(EW, SN) # larger value is in effect
mid_x, mid_y = LL[0]+EW/2.0, LL[1]+SN/2.0 # center location

# the extent preserves the center location
extent = [mid_x-side/2.0, mid_x+side/2.0, mid_y-side/2.0, mid_y+side/2.0]

# this sets square extent
# crs=crg signifies that projection coordinates is used in extent
ax.set_extent(extent, crs=crg)

希望对您有所帮助。

编辑

这是一个完整的工作代码及其生成的 map 。

import matplotlib.pyplot as plt
import cartopy.crs as ccrs
from cartopy.mpl.gridliner import LONGITUDE_FORMATTER, LATITUDE_FORMATTER
import cartopy.io.img_tiles as cimgt

def make_map(projection=ccrs.PlateCarree()):
fig, ax = plt.subplots(figsize=(10, 10),
subplot_kw=dict(projection=projection))
gl = ax.gridlines(draw_labels=True)
gl.xlabels_top = gl.ylabels_right = False
gl.xformatter = LONGITUDE_FORMATTER
gl.yformatter = LATITUDE_FORMATTER
return fig, ax

request = cimgt.StamenTerrain() # very responsive
crg = request.crs #crs of the projection
fig, ax = make_map(projection = crg)

# specify map extent here
lonmin, lonmax = -22, -15
latmin, latmax = 63, 65

LL = crg.transform_point(lonmin, latmin, ccrs.Geodetic())
UR = crg.transform_point(lonmax, latmax, ccrs.Geodetic())
EW = UR[0] - LL[0]
SN = UR[1] - LL[1]
side = max(EW,SN)
mid_x, mid_y = LL[0]+EW/2.0, LL[1]+SN/2.0 #center location

extent = [mid_x-side/2.0, mid_x+side/2.0, mid_y-side/2.0, mid_y+side/2.0] # map coordinates, meters

ax.set_extent(extent, crs=crg)
ax.add_image(request, 8)

# add a marker at center of the map
plt.plot(mid_x, mid_y, marker='o', \
color='red', markersize=10, \
alpha=0.7, transform = crg)

plt.show()

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关于python - 绘制正方形 Cartopy map ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51340015/

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