c - 关于scanf输入的问题

Question

当我执行以下程序时，它获取用户输入的帐户详细信息，然后正确打印它，但它无法读取 opt 值 (y/n)。它会自动再次调用。如何让程序在用户输入“n”时退出？

    char opt;
    do
{

//Getting user input

printf("\n Enter the Account Number:\n ");
scanf("%d",&gAccNo_i);                                       
printf("\n Enter the Account Holder's Name:\n ");
scanf("%s",gCustName_c);
printf("\n Enter the Balance Amount:\n ");
scanf("%f",&gBlncAmt_f);

//Printing the input data.

printf("\n Account Number     : %d",gAccNo_i);
printf("\n Customer Name      : %s",gCustName_c);
printf("\n Balance Amount     : %f",gBlncAmt_f);

printf("\n Do u want to wish to continue?(y/n)");
scanf("%c",&opt);
}while(opt!='n');

Answer 1

使用 opt=getch(); 代替 scanf("%c",&opt);

或

scanf 读取前一行留在缓冲区中的空白。要跳过空格，请在“%c”中添加一个空格:

scanf(" %c", &opt);