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c - 从返回 strstr NULL 的 for 循环中跳出

转载 作者:太空宇宙 更新时间:2023-11-04 02:15:18 25 4
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我没有得到什么?

这很好用:

for ( i = 0; i < 5 && found != 0 ;++i ){ no difference than above
found=strcmp( name, myContacts[i].cFirstName);
printf(" i %d\n", i);
}
printf(" \nName Found %s", myContacts[i-1].cFirstName );

但出于好奇,我也尝试使用 strstr()。

/*** This achieves the same functionality as above ***/

for ( i = 0; i < 5 ;i++ ){
found2=strstr( myContacts[i].cFirstName , name);
printf(" i %d\n", i);
if (found2 != NULL)
{
printf(" \nName Found %s", myContacts[i].cFirstName );
break;
}
}

但是这不起作用:

for ( i = 0; i < 5 && found2 != '\0' ;i++ ){ //this does not work as above
for ( i = 0; i < 5 && found2 != NULL ;i++ ){ // this also is not wroking
found2=strstr( myContacts[i].cFirstName , name);
}

printf(" \nName Found %s", myContacts[i].cFirstName );

提前感谢您的建议。

完整代码:

# please take my codes with a grain of skepticism, I am still learning 
# i know of sizeof(), but I rather not use it just for the purpose of my exercise

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>

#define MAXBUFFERSIZE 10

typedef struct contact {

char cFirstName[10];
char cLastName[10];
char cTelphone[12];

} address ; // end type

// function prototype
void printContacts( address * );
void printMenu();
char getChoice();
void storeContact( address [] , int *);
//int searchContact( address [] , char * );
void searchContact( address [] , char [] );

int main(){

char cSelection = 0;
address myContacts[5];
char buffer[MAXBUFFERSIZE];

int i ;
// initialize array to be zeros
for ( i = 0; i < 5 ; i++ ){
strcpy(myContacts[i].cFirstName, "0");
strcpy(myContacts[i].cLastName,"0");
strcpy(myContacts[i].cTelphone,"0");
}

strcpy(myContacts[0].cFirstName, "Jonny");
strcpy(myContacts[1].cFirstName, "Julia");
strcpy(myContacts[2].cFirstName, "Claudia");
strcpy(myContacts[3].cFirstName, "Aaron");
strcpy(myContacts[4].cFirstName, "Sebastian");

int iDel = -1 ; // store the position if one deleted
int iCount = 0 ; // counter for position in the array, when
// inserting names.

while ( cSelection != '5' ) {
printMenu();
cSelection = getChoice();

switch (cSelection) {
case '1':
printContacts( myContacts );
break;

case '2':
if ( ( iDel >= -1 ) && ( iCount < 5 ) ){
//printf("\niCount is %d ", iCount);
storeContact( myContacts, &iCount );
iCount++;
//printf("\nOutside storeContact, *Plocation %d", iCount );
}
if ( iCount >= 5 ) {
printf("\nThe Memory is full, consider deleting some"\
"Contacts");
}
break;

case '3':
{
printf("\nEnter a name or part of a name to search:\n");
fscanf(stdin, "%s", buffer);
getchar(); // clear the last enter
printf("\nThe line you entered was:\n");
printf("%s\n", buffer);
searchContact( myContacts, buffer );
break;
}
case '4':
//iDel=deleteContact( myContacts );
break;

}// end of switch
}// end of while
return 0;
} // end main

char getChoice(){

char cSelection = 'q'; //for the menu
/**** always scanf CHARS so you can check
* if digit or char !!! ****/

scanf("%s", &cSelection);

while ( strlen(&cSelection) != 1 ){
printf("\nChoich not understood, enter a number again:");
scanf("%s",&cSelection);
}

if ( isalpha(cSelection) ){
printf( "You entered a letter of the alphabet\n" );
cSelection = -1;
printf( "Illegal choice !!!" );
}

return cSelection;
}

void printContacts( address * myContacts ){

int i ;

for ( i = 0; strcmp(myContacts[i].cFirstName,"0") != 0 && i < 5 ; i++ ){
printf("\nmyContacts[%d].cFirstName: %s", i, \
myContacts[i].cFirstName );
}// end for
}

void printMenu(){
printf("\n\n\tSilly Phone Book\n\n");
printf("\n\n1\tPrint Phone Book\n");
printf("2\tAdd New Contact\n");
printf("3\tSearch For Contact\n");
printf("4\tDelete Contact\n");
printf("5\tQuit\n");
printf("\nSelect Action: ");
}

//void storeContact( address myContacts[] ){ //syntactic sugar
void storeContact( address * myContacts, int *Plocation ){

char ch; /* handles user input */
char buffer[MAXBUFFERSIZE]; /* sufficient to handle one line */
int x = 0;
x=*Plocation;

ch = getchar(); // clear the last enter
printf("Enter a name (<10 characters)\n");
//ch = getchar();
//char_count = 0;
//while( (ch != '\n') && (ch != EOF ) && (char_count < MAXBUFFERSIZE)) {
//buffer[char_count++] = ch;
//ch = getchar();
//}
//buffer[char_count] = 0x00; /* null terminate buffer */

//fgets(buffer,11,stdin);

fscanf(stdin, "%s", buffer); /* read from keyboard */

printf("\nThe line you entered was:\n");
printf("%s\n", buffer);

//TODO: add check that string is not too long!!!
// if we do that, the code won't blow here ?

strcpy(myContacts[x].cFirstName, buffer);
}

//int searchContact( address * myContacts, char name[] ){
void searchContact( address * myContacts, char * name ){
int found;
char *found2;
//printf("\nHey dude im buffer from inside searchContact: %s", name);
// iterate throught the array, print possible matches
int i = 0;


//for ( i = 0; i < 5 && found != 0 ;i++ ){
//for ( i = 0; i < 5 && found != 0 ;++i ){ no difference than above
//found=strcmp( name, myContacts[i].cFirstName);
//printf(" i %d\n", i);
//}
//printf(" \nName Found %s", myContacts[i-1].cFirstName );

/*** This achieves the same functionality as above

for ( i = 0; i < 5 ;i++ ){
found2=strstr( myContacts[i].cFirstName , name);
printf(" i %d\n", i);
if (found2 != NULL)
{
printf(" \nName Found %s", myContacts[i].cFirstName );
break;
}
} ***/

for ( i = 0; i < 5 && &found2 != '\0' ;i++ ){ //this does not work as above
found2=strstr( myContacts[i].cFirstName , name);
printf("found %p i %d\n", found2, i);
//printf(" \nName Found %s", myContacts[i].cFirstName );
}

//return found;
} // end of searchContacts if ( isalpha(cSelection) ){
printf( "You entered a letter of the alphabet\n" );
cSelection = -1;
printf( "Illegal choice !!!" );
}

return cSelection;
}

void printContacts( address * myContacts ){

int i ;

for ( i = 0; strcmp(myContacts[i].cFirstName,"0") != 0 && i < 5 ; i++ ){
printf("\nmyContacts[%d].cFirstName: %s", i, \
myContacts[i].cFirstName );
}// end for
}

void printMenu(){
printf("\n\n\tSilly Phone Book\n\n");
printf("\n\n1\tPrint Phone Book\n");
printf("2\tAdd New Contact\n");
printf("3\tSearch For Contact\n");
printf("4\tDelete Contact\n");
printf("5\tQuit\n");
printf("\nSelect Action: ");
}

//void storeContact( address myContacts[] ){ //syntactic sugar
void storeContact( address * myContacts, int *Plocation ){

char ch; /* handles user input */
char buffer[MAXBUFFERSIZE]; /* sufficient to handle one line */
int x = 0;
x=*Plocation;

ch = getchar(); // clear the last enter
printf("Enter a name (<10 characters)\n");
//ch = getchar();
//char_count = 0;
//while( (ch != '\n') && (ch != EOF ) && (char_count < MAXBUFFERSIZE)) {
//buffer[char_count++] = ch;
//ch = getchar();
//}
//buffer[char_count] = 0x00; /* null terminate buffer */

//fgets(buffer,11,stdin);

fscanf(stdin, "%s", buffer); /* read from keyboard */

printf("\nThe line you entered was:\n");
printf("%s\n", buffer);

//TODO: add check that string is not too long!!!
// if we do that, the code won't blow here ?

strcpy(myContacts[x].cFirstName, buffer);
}

//int searchContact( address * myContacts, char name[] ){
void searchContact( address * myContacts, char * name ){
int found;
char *found2;
//printf("\nHey dude im buffer from inside searchContact: %s", name);
// iterate throught the array, print possible matches
int i = 0;


//for ( i = 0; i < 5 && found != 0 ;i++ ){
//for ( i = 0; i < 5 && found != 0 ;++i ){ no difference than above
//found=strcmp( name, myContacts[i].cFirstName);
//printf(" i %d\n", i);
//}
//printf(" \nName Found %s", myContacts[i-1].cFirstName );

/*** This achieves the same functionality as above

for ( i = 0; i < 5 ;i++ ){
found2=strstr( myContacts[i].cFirstName , name);
printf(" i %d\n", i);
if (found2 != NULL)
{
printf(" \nName Found %s", myContacts[i].cFirstName );
break;
}
} ***/

for ( i = 0; i < 5 && found2 != '\0' ;i++ ){ //this does not work as above
found2=strstr( myContacts[i].cFirstName , name);
printf("found %p i %d\n", found2, i);
//printf(" \nName Found %s", myContacts[i].cFirstName );
}

//return found;
} // end of searchContacts

为了本次讨论的完整性,我添加了最终真正符合我要求的内容。这是在完成所有答案之后得出的,所以感谢大家:

我忘了初始化指针:

char *found2=NULL;

现在以下循环按预期工作:

 for ( i = 0; i < 5 && !found2 ;i++ ){ //this does work as above

found2=strstr( myContacts[i].cFirstName , name);
printf("i %d\n", i);

}
printf("Name found %s", found2);

我希望 strstr() 具有此功能,因为现在我可以搜索“Clau”并将其与“Claudia”匹配。这比 strcmp() 更能满足我的需求,尽管我很确定它也可以用 strcmp() 来完成,而且我的 C 语言技能比我更成熟。

再次感谢您的回答!

最佳答案

你的 found2char * .

你应该写for (i = 0; i < 5 && !found2; i++) //etc etc

(或在循环中测试 found2,如果非 NULL 则中断)

关于c - 从返回 strstr NULL 的 for 循环中跳出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8567415/

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