c - C中的八进制到十进制

Question

我稍微修改了代码，得到了下面的内容。输出的数字现在更真实了，但仍然不正确(例如，输入 54# 结果输出 36，而它应该输出 44)

#include <stdio.h>
#include <math.h>

main()
{
    printf("Please enter an octal number ending with # \n");
    int nextNum = getchar();
    int number[100];
    int numberOfSlots = 0; //Records how many digits are entered
    int power = 0; //Sets power of 8 during conversion
    int decimalNumber = 0;
    int i=0;

    while(nextNum != '#') //reads in the whole number, putting the characters together to form one Octal number.
        {
             if(nextNum >='0' && nextNum <='9')
                nextNum = (nextNum - '0');
             else{printf("Oops! That's not a valid number!");}

             number['i'] = (nextNum);
             //numberOfSlots++;
             i++;
             nextNum = getchar();
printf("%d\n", number['i']);

    }


    //Begin converson from Octal to Decimal

    for(i; i > 0; i--)
    {
        decimalNumber = decimalNumber + (number['i'] * pow(8,power));
        power++;
    }

    printf("%d", decimalNumber);

}

Answer 1

由于这是作业，所以我会给出提示而不是答案:

函数getchar()返回一个字符而不是一个数字。字符具有基于系统字符编码的值(参见 ASCII )。

查看实际分配给数字的值，并将您得到的值转换为实际应有的数值。