c - C中的动态程序

Question

大家好，我已经编辑了问题。这是我的全部代码。我已经为我的程序提供了基本的可读性。我希望你们能理解这个程序。

#include<stdio.h>
#include<stdlib.h>
int Max_Min(int,int,int,int *, int *);
int *Max,Number;
int main()
{
    int n1, n2,Maximum_Element=0,*Max;
    int i = 0, j = 0;
    scanf("%d",&Number);
    Max =(int *) malloc(sizeof(int)*Number);//Array Max is created

        for (int k = 0;k <(Number/2);k++)
            {
            scanf("%d", &n1);
            scanf("%d", &n2);
            Max[k] = Max_Min(0,1,0,&n1,&n2);//Passing integer elements n1,n2 with flag 0
            }

    Maximum_Element=Max_Min(1,1,((sizeof(Max)*Number)/8),Max,Min);//Passing array elements Max,Min with flag 1 to function Max_Min

        printf("Maximum_Element=%d", Maximum_Element);
    return 0;
}

int Max_Min(int flag,int Max_Min_flag,int length,int *n1,int *n2)//n1 and n2 should be able to handle array and integers
{
    int i=0,j = 0,k1,k2,Min1 = 0, Min2 = 0,count=0, Not_Zero = 0,x=0,y=0, *New_Max = 0,*New_Min;

/*Recursive Loop for splitting the array elements and calling the array */
       if (flag == 1)
          {
           New_Max = (int *)(malloc(sizeof(int)*length));

        for (;i <= ((length) / 2);i = i + 2)//
          {
            k1 = n1[i];
            j = i + 1;
            if (j <= ((length + 1) / 2))
            {
                k2 = n1[j];
                New_Max[count] = Max_Min(0, 1, 0, &k1, &k2);//It is passing integer elements with flag 0 to function Max_Min 
                count++;
            }
        }
        New_Max[count] = n1[j + 1];


        for (int i = 0;i < count + 1;i++)
        {
  **/* Problem is assigning Max[i]=New_Max[i] is not getting assigned*/**
                Max[i] = New_Max[i];//Copying from New_Max to Max because New_Max will be overwritten,so possible chaunce of dataloss
                Not_Zero++;
            }

        while ((sizeof(Max) / 4 - (Not_Zero))>0)
        {
            Max[Not_Zero] = 0;
            Not_Zero++;
        }
        /*Logic for calling recursive functions based on the count*/
            if (count > 1)
               {
                count--;
                Max_Min(1, 1, count, Max, Min);//Calling Recursive function by Passing Entire Arrays with flag 1.
                }
            else if (count == 1 && Max[1] == 0)
              {
            *n1 = Max[0];
            *n2 = Min[0];
              }
           else if (count == 1 && Max[2] == 0)
             {
            Max_Min(1, 1, count + 1, Max, Min);
            count--;
            }

    }
/*Logic for Finding Maximum & Minimum element is present down*/
        if (flag == 0)
        {
            printf("flag");
            if (Max_Min_flag == 1)
            {
                if (*n1 > *n2)
                {

                }
                else if ((*n1 < *n2) && Max_Min_flag == 1)
                {
                    int temp = 0;
                    temp = *n1;//5
                    *n1 = *n2;//7
                    *n2 = temp;//5
                }
            }
            else if (Max_Min_flag == 2)
            {

                if (*n1 > *n2)//7>2
                {
                    int temp = 0;
                    temp = *n1;//2
                    *n1 = *n2;//2
                    *n2 = temp;//2,7

                }
                else if (*n1 < *n2)
                {

                }
            }
        }
    return *n1;//7
}

问题是在函数 Max_Min() 中分配 Max[i]=New_Max[i]。它显示运行时错误为“访问冲突写入位置 0x00000000。”

Answer 1

首先你需要#include <stdlib.h>使用 malloc

您必须在使用前声明您的函数。

func必须返回 int* .

也在 func 中“n”、第一个“Max”和第二个“Max”需要是同一个变量。将“n”重命名为“最大”

这是用额外的 printf 更正的代码;

#include <stdio.h>
#include <stdlib.h>

int *Max,Number=5;

int* func(int *Max)
{
   for(int j=0;j<5;j++)
      Max[j]=j;//Its not working in this line 
   return Max;
}

int main()
{
   Max=(int *) malloc(sizeof(int)*Number);

   for(int i=0;i<5;i++)
      Max[i]=i;

   int* x = func(Max);

   for(int i=0;i<5;i++)
      printf("%d", x[i]);
}