c - 每行打印 60 个字符

Question

我编写了一个从用户那里获取文本文件的程序。

然后它应该一次打印 60 个字符，然后换行开始，然而，即使它有效

一些单词超过了这个限制然后它把单词切成两半然后开始

再次换行。所以我需要我的程序从根本上弄清楚

该词是否符合 60 个字符的限制，因此不会拆分任何词。

#include <stdio.h>
#include <stdlib.h>
int main( void )
{
char ch, file_name[25];
FILE *fp;
printf("Enter file name: \n");
scanf("%24s" ,file_name);

if ( (fp = fopen(file_name,"r")) == NULL ){
     perror("This file does not exist\n");
     exit(EXIT_FAILURE);}

int c, count;

count = 0;
while ( (c = fgetc(fp)) != EOF ) {
    if ( c == '\n' )
        putchar( ' ' );
    else
        putchar( c );

    count++;
    if ( count == 60 ) {
        putchar( '\n' );
        count = 0;
    }
}
putchar( '\n' );
fclose(fp);
}

Answer 1

#include <stdio.h>
#include <stdlib.h>
int readWord(FILE *fp,char *buff,char *lastChar){
    char c;
    int n=-1;
    *buff=0;
    *lastChar=0;
    while((c= fgetc(fp))!=EOF){
        n++;
        if(isspace(c)){
            /*
                you may keep tabs or replace them with spaces
            */
            *lastChar=c;
            break;
        }       
        buff[n]=c;
        buff[n+1]=0;
    }
    return n;
}


int main( void ) {
    char ch, file_name[25];
    char buff[50];
    int pos=0;
    FILE *fp;
    printf("Enter file name: \n");
    gets(file_name);

    if ( !(fp = fopen(file_name,"r")) ) {
        perror("This file does not exist\n");
        exit(EXIT_FAILURE);
    }

    int c, count;

    count = 0;
    while ( (pos=readWord(fp,buff,&ch))!=EOF) {
        count+=pos+(!!ch);
        if(count>60){
            printf("\n");
            count=pos;
        }

        if(ch){
            printf("%s%c",buff,ch);
        }else{
            printf("%s",buff);
        }
        if(!pos){
            count=0;
        }

    }
    putchar( '\n' );
    fclose(fp);
    return 0;
}