python - 使用 BeautifulSoup 从标签中提取 'href'

Question

我在 html 中有以下标签，我只想提取 href 内容，即 Quatermass_2_Vintage_Movie_Poster-61-10782 和 Hard Day's Night

<span class="small">
                                Ref.No:10782<br/>
<a href="Quatermass_2_Vintage_Movie_Poster-61-10782" title="Click for more details and a larger picture of Quatermass 2">
                                Click for more details and a larger picture of <b>Quatermass 2</b>
</a>
</span>, <span class="small">
                                Ref.No:10781<br/>
<a href="Hard_Day__039_s_Night_Vintage_Movie_Poster-61-10781" title="Click for more details and a larger picture of Hard Day's Night">
                                Click for more details and a larger picture of <b>Hard Day's Night</b>
</a>
</span>

下面的 python 代码使我能够只找到整个标签

html = ['table2.html']

with open("table2.html", "r") as f:
    contents = f.read()


soup = BeautifulSoup(contents, "lxml")

for name in soup.find_all("span", {"class": "small"}):
    print(name)

但是无法仅选择 href。我试过了

for name in soup.find_all("span", {"class": "small"}.get(href)):
    print(name) 

我也试过将 href 引用放在打印语句中

for name in soup.find_all("span", {"class": "small"}:
    print(name.get('href'))         

有好心人帮忙吗？

Answer 1

获取span标签后，您需要找到a标签，然后获取href属性。

像这样的东西会起作用:

for name in soup.find_all("span", {"class": "small"}):
    print(name.find("a").get("href"))