最明确定义 var 时的 Python NameError

Question

def make_pdf(self):
        self.get_filez()
        self.get_client()
        file_name = self.client_id+"_"+self.client_name+"_"+self.batch_num
        style = libxslt.parseStylesheetDoc(self.xsl_file)   
        transformation = style.applyStylesheet(self.xml_file,None)
        style.saveResultToFilename("tmp/"+file_name+".fo",transformation,0)
        style.freeStylesheet()
        self.xml_file.freeDoc()
        transformation.freeDoc()
        fop_cmd = "/usr/bin/xmlgraphics-fop"
        #file_name = self.tpa+"_"+self.be+"_"+self.batch_num
        cmd = [fop_cmd,"-fo","tmp/"+file_name+".fo","-pdf","tmp/"+file_name+".pdf"]
        #fop_transform = subprocess.Popen(cmd,stdout=subprocess.PIPE,stderr=subprocess.STDOUT)
        #fop_log = "-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-\n"
        #fop_log = fop_log + time.strftime('%Y-%m-%d %R:%S')+"\n"
        #fop_log = fop_log + file_name+".fo" + "\n"
        #fop_log =  fop_transform.communicate()[0]+"\n"
        #f = open("/tmp/error_log","a")
        #f.write(fop_log)
        #f.close()

好的，如果我注释掉 cmd 变量声明，代码将运行并正确生成一个 fo 文件。像上面一样没有注释，我得到一个 NameError on file_name is not defined (它在顶部)。如果我取消注释 cmd 声明正上方的 file_name 的第二个声明，它会在自身上抛出一个 NameError。 '.'过去发生这种事情时，是语法错误。我想念它，请帮忙!

当 file_name 的第二个声明被注释掉时:

Traceback (most recent call last):
  File "make_pdfs.py", line 11, in ?
    from MakePdfs import MakePdfs
  File "/home/khouser/removed/removed/MakePdfs.py", line 16, in ?
    class MakePdfs:
  File "/home/khouser/removed/removed/MakePdfs.py", line 39, in MakePdfs
    cmd = [fop_cmd,"-fo","tmp/"+file_name+".fo","-pdf","tmp/"+file_name+".pdf"]
NameError: name 'file_name' is not defined

当 file_name 的第二个声明被取消注释时:

Traceback (most recent call last):
  File "make_pdfs.py", line 11, in ?
    from MakePdfs import MakePdfs
  File "/home/khouser/removed/removed/MakePdfs.py", line 16, in ?
    class MakePdfs:
  File "/home/khouser/removed/removed/MakePdfs.py", line 38, in MakePdfs
    file_name = self.tpa+"_"+self.be+"_"+self.batch_num
NameError: name 'self' is not defined

Answer 1

神秘的 NameErrors 可能来自您的文件包含不可见的控制字符。在 unix 机器上，您可以通过查看

的输出来发现这些错误

cat -A filename.py