c - pthread_create 不接受参数

Question

我正在尝试创建一个 pthread，但我对创建它所需的参数感到困惑。

我试图将多个参数传递给 pthread 的入口函数，并将其封装到一个结构中。但是，pthread_create 不接受它。

以下是我的代码的相关部分:

    Customer_Spawn_Params *params = (Customer_Spawn_Params*) malloc(sizeof(Customer_Spawn_Params));
    params->probability = chance;
    params->queue = queue;

    pthread_t customer_spawn_t;
    if (pthread_create(&customer_spawn_t, NULL, enqueue_customers, &params)) {
    }

这里是 Customer_Spawn_Params 结构:

 typedef struct {
        Queue *queue;
        double probability;
} Customer_Spawn_Params;

最后，这里是 enqueue_customers()，它接受指向 Customer_Spawn_Params 结构的指针:

    void *enqueue_customers(Customer_Spawn_Params *params) {
        int customer_id = 0;
        double probability = params->probability;
        Queue *queue = params->queue;
        while(true) {
                sleep(1);
                bool next_customer = next_bool(probability);
                if (next_customer) {
                        Customer *customer = (Customer*) malloc(sizeof(Customer));
                        customer->id = customer_id;
                        enqueue(queue, customer);
                        customer_id++;
                }
        }
        return NULL;
}

Answer 1

第 1 点。

if (pthread_create(&customer_spawn_t, NULL, enqueue_customers, &params))

改为

if (pthread_create(&customer_spawn_t, NULL, enqueue_customers, params))。

因为，params 本身就是一个指针。

第 2 点:

此外，

void *enqueue_customers(Customer_Spawn_Params *params)

应该是

void *enqueue_customers(void *params)

在您的函数中，您必须将其类型转换回实际的指针，例如，

void *enqueue_customers(void *params)
{
   Customer_Spawn_Params *p = params;