python - 如何找到领带游戏python

Question

您好，我正在制作这款井字游戏，我看了一些教程，但没有任何游戏可以以平局结束关于我的芬兰语变量和评论

import random

board = [0,1,2,
3,4,5,
6,7,8]

def show():
    print board[0], '|',board[1],'|',board[2]
    print '----------'
    print board[3], '|',board[4],'|',board[5]
    print '----------'
    print board[6], '|',board[7],'|',board[8]

def checkLine(char, spot1, spot2, spot3):
    if (board[spot1] == char) and (board[spot2] == char) and (board [spot3] == char)    :
        return True
    else:
        return False

def checkAll(char):
    ret = False
    if checkLine(char, 0, 1, 2):
        ret = True
    if checkLine(char, 0,3, 6):
        ret = True
    if checkLine(char, 1, 4, 7):
        ret = True
    if checkLine(char, 2, 5, 8):
        ret = True
    if checkLine(char, 6, 7, 8):
        ret = True
    if checkLine(char, 3, 4, 5):
        ret = True
    if checkLine(char, 2, 4, 6):
        ret = True
    if checkLine(char, 0, 4, 8):
        ret = True
    return ret

moves = range(9) 
numindex = 1
ratkennut = False
while moves:
    show()

    input = raw_input("Put x: ")
    try:
        val = int(input)
        input = int(input)
    except ValueError:
        print("Input number!")
        input = raw_input("Put x: ")
        input = int(input)
    if input in moves:
        moves.remove(input)

    if board [input] != 'x' and board[input] != 'o':
        board[input] = 'x'

        if checkAll('x') == True:
            print "~~ X Won ~~"
            ratkennut = True
            break;

        while moves:
            random.seed() #Gives opponents move
            opponent = random.choice(moves)
            moves.remove(opponent)

            if board[opponent] != 'o' and board[opponent] != 'x':
                board[opponent] = 'o'

                if checkAll('o') == True:
                    print "~~ O Won ~~"
                    ratkennut = True
                break;
    else:
        print 'This  spot is taken'
else:
    print "Tie!"

问题:当游戏以 tie game 结束时，这段代码有什么问题它卡住了，我需要 ctrl + c 如何让它找到 tie game 并打印“tie game”我对其进行了编辑，现在效果非常好!

Answer 1

您在 while 循环中为对手选择的 randint 移动选择可能会无限期地运行，尤其是当剩余的有效移动数变少时。取而代之的是，制作一个有效 Action 列表，list.remove() 中的每个 Action :

moves = range(9) 

这简化了用户的移动:

if input in moves:
    moves.remove(input)

对手的举动:

opponent = random.choice(moves)
moves.remove(opponent)

并确定游戏结束:

while moves:
    ...
else:
    print "It's a tie."