c - (C程序设计)用户名和密码识别

Question

为什么我得到 format '%s' expects argument of type 'char*'？我应该如何解决这个问题？

这是我的代码:

char UserName[] = "iluvcake";
scanf("%s", &UserName);
printf("Please enter your password: \n");
char PassWord[] = "Chocolate";
scanf("%s", &PassWord);
    //if...else statement to test if the input is the correct username. 
    if (UserName == "iluvcake") 
    {
     if (PassWord == "Chocolate"){
     printf("Welcome!\n");
    }
    }else
    {
     printf("The user name or password you entered is invalid.\n");
    }

Answer 1

&UserName 是指向 char 数组(即 char**)的指针。你应该使用

scanf( "%s", UserName );