python - 使用 Python 邮箱模块保存 IMAP 消息

Question

我正在使用 imaplib 从 IMAP 下载邮件到 mbox(使用 mailbox 模块):

import imaplib, mailbox
svr = imaplib.IMAP4_SSL('imap.gmail.com')
svr.login('myname@gmail.com', 'mypaswword')
resp, [countstr] = svr.select("[Gmail]/All Mail", True)

mbox = mailbox.mbox('mails.mbox')

for n in range(...):
  resp, lst1 = svr.fetch(n, 'UID')    # the UID of the message
  resp, lst2 = svr.fetch(n, '(RFC822)')   # the message itself
  mbox.add(lst2[0][1])      # add the downloaded message to the mbox
  #
  # how to store the UID of this current mail inside mbox? 
  #

让我们下载 UID = 1 .. 1000 的邮件。下一次，我想从第 1001 条消息开始，而不是从第 1 条开始。但是，mailbox.mbox 不会将 UID 存储在任何地方。所以下次我打开 mbox 文件时，就不可能知道我们在哪里停止了。

模块 mailbox 是否有一种自然的方式来存储电子邮件的 UID？

或者我没有按应有的方式使用 mailbox + imaplib ？

Answer 1

希望有用:

1) 库和环境 Win7 Anaconda3-4.3.1-Windows-x86_64.exe (new is available but that I have used

2) 列出所有邮箱:

import getpass, imaplib, sys

def main():
      hostname = 'my.mail.server'
      username = 'my_user_name'
      m = imaplib.IMAP4_SSL(hostname)
      m.login(username, 'passowrd')

   try:
      print('Capabilities:', m.capabilities)
      print('Listing mailboxes ')
      status, data = m.list()
      print('Status:', repr(status))
      print('Data:')
      for datum in data:
         print(repr(datum))

   finally:
      m.logout()

if __name__ == '__main__':
   main()

3) 使用以上生成的信息，我们可以将邮件服务器中的所有电子邮件转储到目录中:

import getpass, imaplib, sys, email, os , io
import codecs

BASE_NAME = 'msg_no_'
BASE_DIR = 'D:/my_email/'

def writeTofile(mailDir, partOfName, msg ):

   ## no need of dos backslash -- newDir = BASE_DIR + mailDir.replace('/', '\\')

   newDir = BASE_DIR + mailDir

   if not os.path.exists(newDir):
       os.makedirs(newDir)

   os.chdir(newDir)

   # print('Dir:' + os.getcwd() )

   file_name = BASE_NAME + partOfName  + '.eml'

   # print('Write:' + file_name)

   fw = open(newDir + '/' + file_name,'w', encoding="utf-8")
   fw.write( msg )
   fw.close()

   return


def processMailDir(m, mailDir):

   print('MailDIR:' + mailDir)

   m.select(mailbox=mailDir, readonly=True)
   typ, data = m.search(None, 'ALL')

   for num in data[0].split():
      typ, data = m.fetch(num, '(RFC822)')
      msg = email.message_from_bytes(data[0][1])

      smsg = msg.as_bytes().decode(encoding='ISO-8859-1')

      writeTofile(mailDir, num.decode(), smsg )

   m.close()

   return


def main():

   if len(sys.argv) != 3:
      hostname = 'my.mail.server'
      username = 'my_username'
      m = imaplib.IMAP4_SSL(hostname)
      m.login(username, 'password')

   else:
      hostname, username = sys.argv[1:]
      m = imaplib.IMAP4_SSL(hostname)
      m.login(username, getpass.getpass())

   try:
      print('Start...')

      processMailDir(m, 'INBOX')
      processMailDir(m, 'Sent')
      processMailDir(m, 'archive/2013/201301')
      processMailDir(m, 'archive/2013/201302')
# etc.. etc.. simple as it can be but not simpler
      print('Done...')

   finally:
      m.logout()

if __name__ == '__main__':
   main()

上面会将您的电子邮件转储到:D:\my_email\INBOX\msg_no_1.eml ... msg_no203.eml

然后你需要这个 secret 来打开 Windows 上的 eml:

Administrator: cmd.com:

assoc .eml=Outlook.File.eml
ftype Outlook.File.eml="C:\Program Files (x86)\Microsoft Office\Office12\OUTLOOK.EXE" /eml "%1"

亲爱的 stockoverflow 审查员 - 请大发慈悲，我会发现以上有用；例如:smsg = msg.as_bytes().decode(encoding='ISO-8859-1') 花了很长时间才弄明白。