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python - Pandas HDFStore 从嵌套列中选择

转载 作者:太空宇宙 更新时间:2023-11-04 01:07:47 29 4
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我有以下 DataFrame,它作为名为数据的 frame_table 存储在 HDFStore 对象中:

      shipmentid qty            
catid 1 2 3 4 5
0 0 0 0 0 0 0
1 1 0 0 0 2 0
2 2 2 0 0 0 0
3 3 0 4 0 0 0
0 0 0 0 0 0 0

我想执行 store.select('data','shipmentid==2'),但我收到“shipmentid”未定义的错误:

ValueError: The passed where expression: shipmentid==2
contains an invalid variable reference
all of the variable refrences must be a reference to
an axis (e.g. 'index' or 'columns'), or a data_column
The currently defined references are: columns,index

编写此 select 语句的正确方法是什么?

编辑:添加示例代码

import pandas as pd
from pandas import *
import random

def createFrame():
data = {
('shipmentid',''):{1:1,2:2,3:3},
('qty',1):{1:5,2:5,3:5},
('qty',2):{1:6,2:6,3:6},
('qty',3):{1:7,2:7,3:7}
}
frame = pd.DataFrame(data)

return frame

def createStore():
store = pd.HDFStore('sample.h5',format='table')
return store

frame = createFrame()
print(frame)
print('\n')
print(frame.info())

store = createStore()
store.put('data',frame,format='t')
print('\n')
print(store)

results = store.select('data','shipmentid == 2')

store.close()

最佳答案

我敢打赌,您已经使用过类似的东西来创建您的商店,

In [207]:

data = pd.DataFrame(np.random.randn(8,2), columns=['shipmentid', 'qty'])
store = pd.HDFStore('borrar')
store.put('data', data, format='t')

如果您随后尝试执行 select 确实会收到您描述的错误,

In [208]:

store.select('data', 'shipmentid>0')

---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-211-5d0c4082cdcf> in <module>()
----> 1 store.select('data', 'shipmentid>0')

...

ValueError: The passed where expression: shipmentid>0
contains an invalid variable reference
all of the variable refrences must be a reference to

相反,您可以这样创建它:

In [209]:

data = pd.DataFrame(np.random.randn(8,2), columns=['shipmentid', 'qty'])
data.to_hdf('borrar2', 'data', append=True, mode='w', data_columns=['shipmentid', 'qty'])
In [210]:

pd.read_hdf('borrar2', 'data', where='shipmentid>0')
Out[210]:
shipmentid qty
1 0.778225 -1.008529
5 0.264075 -0.651268
7 0.908880 0.153306

(老实说,我不知道为什么它以一种方式工作而另一种不工作,我的猜测是在第一种方式中你不能指定数据列。但这是其中一个可以驱使你疯了……)

编辑:更新发布的代码后,数据框有一个 MultiIndex。类似的更新代码类似于:

In [273]:

import pandas as pd
from pandas import *
import random

def createFrame():
data = {
('shipmentid',''):{1:1,2:2,3:3},
('qty',1):{1:5,2:5,3:5},
('qty',2):{1:6,2:6,3:6},
('qty',3):{1:7,2:7,3:7}
}
frame = pd.DataFrame(data)

return frame

frame = createFrame()
print(frame)
print('\n')
print(frame.info())

frame.to_hdf('sample.h5', 'data', append=True, mode='w', data_columns=['shipmentid'], format='table')
pd.read_hdf('sample.h5','data', 'shipmentid == 2')

但是我得到了一个错误(我猜你也得到了同样的结果):

  qty       shipmentid
1 2 3
1 5 6 7 1
2 5 6 7 2
3 5 6 7 3


<class 'pandas.core.frame.DataFrame'>
Int64Index: 3 entries, 1 to 3
Data columns (total 4 columns):
(qty, 1) 3 non-null int64
(qty, 2) 3 non-null int64
(qty, 3) 3 non-null int64
(shipmentid, ) 3 non-null int64
dtypes: int64(4)
memory usage: 120.0 bytes
None
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-273-e10e811fc7c0> in <module>()
23 print(frame.info())
24
---> 25 frame.to_hdf('sample.h5', 'data', append=True, mode='w', data_columns=['shipmentid'], format='table')
26 pd.read_hdf('sample.h5','data', 'shipmentid == 2')
.....
stack trace
.....
ValueError: cannot use a multi-index on axis [1] with data_columns ['shipmentid']

我已经浏览了一下,但我无法为此提供解决方案。我的印象是通过查看 code in github是选项 data_columns 不能与 MultiIndex 结合使用。我能想到的唯一解决方案是像在您的代码中一样写入 HDFStore ,然后读取完整的数据帧,不带任何条件,然后进行搜索。即:

new_frame = store.get('data')
print new_frame[new_frame['shipmentid'] == 2]



<class 'pandas.io.pytables.HDFStore'>
File path: sample.h5
/data frame_table (typ->appendable,nrows->3,ncols->4,indexers->[index])
qty shipmentid
1 2 3
2 5 6 7 2

关于python - Pandas HDFStore 从嵌套列中选择,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29497694/

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