node.js - Nodejs Express : Sending a different page if logged in

Question

我正在尝试使用expressjs 创建一个网站。如果用户已登录，我想向他发送不同的页面。

我可以发送原始 html 网站，但未加载像 index.css 这样的链接文件!

app.use(cookieParser());
app.use(expressSession({secret:'somesecrettokenhere', resave: false, saveUninitialized: true}));
app.use(bodyParser());

//app.use(express.static(path.join(__dirname, '../client/login')));
// disable layout
var mainPage  = express.static(path.join(__dirname, '../client/main'));
var loginPage = express.static(path.join(__dirname, '../client/login'));

app.get('/', function (req, res, next) {
    console.log('getting /');
    if (req.session.userName) {
        //app.use(express.static(path.join(__dirname, '../client/main')));
        console.log("logged in");
        mainPage(req, res, next);
    }else {
        //app.use(express.static(path.join(__dirname, '../client/login')));
        console.log("not logged in");
        loginPage(req, res, next);
    }
});

http.listen(3000, function(){
    console.log('listening on *:3000');
});

提前致谢!

Answer 1

是的，可以。您可以执行 response.render(pageName); 来呈现您想要向用户发送的页面。

app.use(cookieParser());
app.use(expressSession({secret:'somesecrettokenhere', resave: false, saveUninitialized: true}));
app.use(bodyParser());

//app.use(express.static(path.join(__dirname, '../client/login')));
// disable layout
// view engine setup
app.set('views', path.join(__dirname, '../client'));
app.set('view engine', 'jade');
app.get('/', function (req, res, next) {
   console.log('getting /');
   if (req.session.userName) {
       //app.use(express.static(path.join(__dirname, '../client/main')));
       console.log("logged in");
       res.render("mainPage");
    }else {
       //app.use(express.static(path.join(__dirname, '../client/login')));
       console.log("not logged in");
       res.render("loginPage");
   }
});

http.listen(3000, function(){
    console.log('listening on *:3000');
});

我使用的是jade模板引擎，你可以使用任何其他的