Python lxml : How to traverse back up a tree

Question

我有以下python代码

import lxml.etree

root = lxml.etree.parse("../../xml/test.xml")

path="./pages/page/paragraph[contains(text(),'ash')]"
para = root.xpath(path)

一旦我到达了para节点，我就不想再往前走了。现在我想回到根并查看所有 <paragraph>节点。有没有办法回到树上。

或者这样看。我想要 root 之间的子树和 para .我该怎么做？

供引用，这里是xml

<document>
    <pages>
        <page>
            <paragraph>XBV</paragraph>
            <paragraph>GFH</paragraph>
        </page>
        <page>
            <paragraph>ash</paragraph>
            <paragraph>lplp</paragraph>
        </page>
    </pages>
</document>

现在在这种情况下，我想要节点 XBV 和 GFH。这怎么可能？

Answer 1

.. 会让你在树上更上一层楼。

但是，我认为preceding是您正在寻找的东西:

The preceding axis indicates all the nodes that precede the context node in the document except any ancestor, attribute and namespace nodes.

./pages/page/paragraph[contains(text(),'ash')]//preceding::paragraph

示例代码:

import lxml.etree


data = """
<document>
    <pages>

    <page>
       <paragraph>XBV</paragraph>

       <paragraph>GFH</paragraph>
    </page>

    <page>
       <paragraph>ash</paragraph>

       <paragraph>lplp</paragraph>
    </page>

    </pages>
</document>
"""

tree = lxml.etree.fromstring(data)
print [item.text for item in tree.xpath("./pages/page/paragraph[contains(text(),'ash')]//preceding::paragraph")]

打印:

['XBV', 'GFH']