python - 反向未找到，Django，第一次

Question

search.html 是显示搜索结果列表的页面，但是当我点击“搜索”按钮时，它显示错误页面“未找到反向”。我在这里看到了同样的问题，但是代码不同，所以我没有找到问题的解决方案。

def search(request):
if 'q' in request.GET and request.GET['q']:
    q = request.GET['q']
    words = word.objects.filter(title__icontains = q)
    return render_to_response('dictionary/search.html',
        {'words': words, 'query': q })
else:
    return HttpResponse('Please submit a search term.')


def worder(request, word_id):
    showword = get_object_or_404(word, id = word_id)
    return render(request, 'dictionary/worder.html', {'showword': showword})

网址:

urlpatterns = [
url(r'^$', Dictionary.views.home, name='home'),
url(r'^about/$', Dictionary.views.about, name='about'),
url(r'^search/$', Dictionary.views.search, name='search'),
url(r'^worder/(?P<word_id>[0-9]+)/$', Dictionary.views.worder, name='worder')]

{% url 'worder' word_id %} 有问题:

<li class="listofwords"><a class="foundword" href="{% url 'worder' word_id %}">{{ word.title }}</a></li>

Answer 1

您正在使用一个不存在的变量 word_id。您应该使用 word.id，它是您的对象词的 ID:

<li class="listofwords"><a class="foundword" href="{% url 'worder' word.id %}">{{ word.title }}</a></li>