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c - 即使使用 fflush 也会跳过 scanf

转载 作者:太空宇宙 更新时间:2023-11-04 00:52:05 24 4
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我有一个不接受输入的scanf。该值自动为零,即使变量未初始化也是如此。 scanf 被跳过:

printf("\nEnter the number of the student to be dropped: ");
fflush(stdin);
scanf(" %d ",&choice);
printf("choice is %d", choice);

程序运行时,立即显示“选择为0”。

上面的代码片段取自这段代码中的 drop() 函数:

    #include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct student{
char name[50];
char* course;
};

main()
{
char repeat;
do{
system("cls");
int mainchoice;
printf("Student Enrollment System");
printf("\n");
printf("\n");
printf("1. View\n");
printf("2. Enroll\n");
printf("3. Drop enrollment\n");
printf("Select choice: ");
fflush(stdin);
scanf("%d",&mainchoice);
system("cls");
switch(mainchoice){
case 1:
view();
break;
case 2:
enroll();
break;
case 3:
drop();
break;
default:
printf("Please enter a valid number.");
getch();
fflush(stdin);
break;
}

printf("\nWould you like to make another transaction? [Y/N]: ");
fflush(stdin);
scanf("%c",&repeat);
}while(repeat=='Y'||repeat=='y');
}

view(){
int ctr = count();
printf("Enrolled Students:\n\n");
system("type records.txt");
printf("\n\nNumber of students enrolled: %d", ctr);
getch();
fflush(stdin);

}

enroll(){
int choice;
char validate;
printf("1. Information Technology\n");
printf("2. Computer Science\n");
printf("3. Computer Engineering\n");
printf("4. Information Systems\n");
struct student news;
printf("Name: ");
fflush(stdin);
gets(news.name);
printf("Course Number: ");
fflush(stdin);
scanf("%d", &choice);
switch(choice){
case 1:
news.course = "BSIT";
break;
case 2:
news.course= "BSCS";
break;
case 3:
news.course = "BSCpE";
break;
case 4:
news.course = "BSIS";
break;
default:
printf("Please enter a valid number\n");
break;
}
printf("Enroll %s to %s? [Y/N]:",news.name,news.course);
fflush(stdin);
scanf("%c", &choice);
if(choice=='Y' || choice=='y')
{
FILE * records;
records = fopen("records.txt", "a+");
fprintf(records, "%s, %s\n",news.name,news.course);
fclose(records);
printf("%s has been enrolled to %s\n",news.name, news.course);

}
else
{
printf("You have chosen to cancel your transaction");
}
}

drop(){
printf("Drop Student:\n\n");
int ctr = 0;
int choice; //which student to delete
char c;
FILE * record; // original records.txt
FILE* repo; //temporary data storage


record = freopen("records.txt", "r", stdin);
while((c = fgetchar())!=EOF){
if(c == '\n'){

}
else{
ctr=ctr+1;
printf("%d. ", ctr);
while(1){
printf("%c",c);
c= fgetchar();
if(c=='\n'){
printf("%c",c);
break;
}

}

}
}
fclose(record);
fflush(stdin);
fflush(stdin);
printf("\nEnter the number of the student to be dropped: ");
fflush(stdin);
scanf(" %d ",&choice);
getch();
getch();
fflush(stdin);
ctr = 1;
fflush(stdin);

repo = fopen("temp.txt","w");
record = freopen("records.txt","r",stdin);
while((c = getchar()) != EOF){
if(c == '\n'){

}
else{

while(ctr!=choice){
fprintf(repo,"%c",c);
c= fgetchar();
if(c=='\n'){
fprintf(repo,"%c",c);
ctr = ctr + 1;
break;
}
}
}
}
fclose(record);
fclose(repo);

getch();
}

//counts the number of rows in the record
int count(){
int ctr=0;
char c;
FILE * records;
records = freopen("records.txt","r", stdin);
if(records!=NULL){
while((c=fgetchar()) !=EOF){
if(c=='\n'){
ctr = ctr+1;
}
}
}
fclose(records);
return ctr;
}

执行 fflush 似乎没有帮助。有什么想法吗?

最佳答案

fflush 的行为没有为输入流定义; fflush(stdin) 是一个编码错误,您应该从您的代码中删除这些调用。

扫描单个字符时,在%c转换说明符前添加一个空格;这将告诉 scanf 跳过任何前导空白并读取下一个非空白字符:

scanf(" %c", &choice);

%d%s 转换说明符将跳过任何前导空格。

编辑

自 C99 起不再支持隐式键入,养成这种习惯是个坏习惯。显式键入您的函数,并使用 void 作为参数列表以指定它们不带参数:

main() => int main(void)
view() => void view(void) // void since it isn't returning a value
drop() => void drop(void)

等等

同样,gets 在 C99 中已被弃用,并在 2011 标准中完全消失。使用它在您的程序中引入故障点/主要安全漏洞。请改用 fgets

关于c - 即使使用 fflush 也会跳过 scanf,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14994271/

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