Python 文件 IO - 构建字典并寻找最大值

Question

问题是返回此文本文件中参与者人数最多的事件的名称:

#Beyond the Imposter Syndrome 
32 students 
4 faculty 
10 industries 
#Diversifying Computing Panel
15 students 
20 faculty 
#Movie Night 
52 students 

所以我想我必须将它拆分成一个字典，其中键作为事件名称，值作为其他行开头的整数之和。我遇到了很多麻烦，我想我把它弄得太复杂了。

这是我目前所拥有的:

def most_attended(fname):
    '''(str: filename, )'''
    d = {}
    f = open(fname)
    lines = f.read().split(' \n')
    print lines
    indexes = []
    count = 0
    for i in range(len(lines)):
        if lines[i].startswith('#'):
            event = lines[i].strip('#').strip()
            if event not in d:
                d[event] = []
            print d
            indexes.append(i)
            print indexes
        if not lines[i].startswith('#') and indexes !=0:
            num = lines[i].strip().split()[0]
            print num 
            if num not in d[len(d)-1]:
                d[len(d)-1] += [num]
    print d

    f.close()

Answer 1

import sys
from collections import defaultdict
from operator import itemgetter

def load_data(file_name):
    events = defaultdict(int)
    current_event = None
    for line in open(file_name):
        if line.startswith('#'):
            current_event = line[1:].strip()
        else:
            participants_count = int(line.split()[0])
            events[current_event] += participants_count
    return events


if __name__ == '__main__':
    if len(sys.argv) < 2:
        print('Usage:\n\t{} <file>\n'.format(sys.argv[0]))
    else:
        events = load_data(sys.argv[1])
        print('{}: {}'.format(*max(events.items(), key=itemgetter(1))))