python - 如何在 GTK.Stack 中获取可见子项的索引

Question

能否在Gtk.Stack中获取visible的索引？

例子:

>>> stack = Gtk.Stack()
>>> stack.add_named(any_widget1, 'any_widget1') # Index 0
>>> stack.add_named(any_widget2, 'any_widget2') # Index 1
>>> stack.add_named(any_widget3, 'any_widget3') # Index 2
>>>
>>> stack.get_visible_child_index()
0

这可能吗？

Answer 1

Stack 文档包括 position 子属性:

child = stack.get_visible_child()
if child is not None:
    position = stack.child_get_property(child, "position")