python - 检查字符串包括/不包括来自不同列表的值

Question

listIncludedFolders = ["Criteria1"]
listExcludedFolders = ["Criteria2"]

for dirpath, dirnames, filenames in os.walk(root):

    proceed = False

    for each in listIncludedFolders:
        if each in dirpath:
            proceed = True

    if proceed == True:
        for each in listExcludedFolders:
            if each in dirpath:
                proceed = False

    if proceed == True:
        print(dirpath)

我正在尝试以更 pythonic 的方式实现以下代码。使用生成器，我可以设法基于单个列表的项目继续:

if any(dir in dirpath for dir in listIncludedFolders):
    print(dirpath)

...但我无法添加第二个比较。我在下面设法获得了一个附加条件，但我需要遍历附加条件列表:

if any(dir in dirpath for dir in listIncludedFolders if("Criteria2" not in dirpath)):
    print(dirpath)

我怎样才能“干净利落地”实现这一点？

Answer 1

将两个条件与 and 运算符与另一个 any 调用结合起来:

if any(each in dirpath for each in listIncludedFolders) and \
        not any(each in dirpath for each in listExcludedFolders):
    print(dirpath)

或另一个和调用(条件否定):

if any(each in dirpath for each in listIncludedFolders) and \
       all(each not in dirpath for each in listExcludedFolders):
    print(dirpath)

顺便说一句，(... for .. in .. if ..) 是一个 generator expression , 不是 list comrpehension .