node.js - Mongo .get 返回垃圾

Question

当我从 Postman 之类的东西执行此函数时:

router.get('/db', function(req, res, next) {

    tune.find({}, function (err, results) {
        res.json(results);
    });

});

我的数据库返回此:

[{"_id":"56f30425ba97bb301fe6ab1a","__v":0},    
{"_id":"56f30514f9b7ea3b1f1fd9f7","__v":0},    
{"_id":"56f306bb9c8203451f2cc58a","__v":0},
{"_id":"56f306ca9c8203451f2cc58b","__v":0},
{"_id":"56f306e99c8203451f2cc58c","__v":0},
{"_id":"56f33d43b64d540b208b6c3c","__v":0}]

我的 Mongoose 架构:

var Schema = mongoose.Schema;
var track = new Schema({
    title: String,
    artist: String,
    genre: String
});
var tune = mongoose.model('tune', track);

我的帖子:

router.post('/db', function(req, res, next) {
    var tune1 = new tune(req.body);
    tune1.save(function (err) {
        if (err) { console.log('error!');}
        else {
            res.json({message: 'Track successfully posted'});
        }
    });
});

请求帖子:

app.use('/users', userRoutes);

var options = { method: 'POST',
    url: 'http://localhost:3000/users/db',
    headers:
    { 'content-type': 'application/x-www-form-urlencoded',
        'postman-token': '',
        'cache-control': 'no-cache' },
    form: { title: '000000', artist: 'blah blah', genre: 'rap' } };

request(options, function (error, response, body) {
    if (error) throw new Error(error);

    console.log(body);
});

当我从 Postman 执行 post 命令时，我收到一条成功的 post 消息。这只是我返回 JSON 的方式吗？我希望能够查看数据库中每个帖子的标题、艺术家和流派。

谢谢

Answer 1

在这种情况下，Mongoose 根本没有保存您所期望的内容。尝试在调试器中查看 req.body 和 tune1 以确保获得预期结果。

在您的架构中将 strict 设置为 'throw' 也可能会有所帮助，这样当我们尝试保存无效的tune 时就会收到错误消息:

var track = new Schema({
    title: String,
    artist: String,
    genre: String
}, {
    strict: 'throw'
});