Python猜谜游戏，用字母替换空格存入列表

Question

基本上我正在尝试制作刽子手类型的游戏。当猜到单词中的字母时，我希望该字母在下一轮中留在那里。我试着用一个列表来做这件事，但我不知道如何让它用字母替换特定的空白。

是的，我已经阅读了有关该主题的其他问题，但无法让它们为我工作。

import random
import time

def intro():
    print ('''Welcome to the word guessing game!
    You will have 6 letter guesses to figure out my word!
    First you must choose a topic.
    Choose from the following: (1) Cars , (2) Diseases ,
    (3) Animals , or (4) Mathematical Words''')

def optionSelect():
    choice = ''
    while choice != '1' and choice != '2' and choice !='3' and choice !='4':
        choice = input()
    return choice

def checkChoice(chosenOption):
    if chosenOption == '1':
        sectionOne()
    elif chosenOption == '2':
        sectionTwo()
    elif chosenOption == '3':
        sectionThree()
    elif chosenOption == '4':
        sectionFour()
    else:
        print('You didnt choose an option...')

def sectionOne():
    words = ['mclaren ', 'bugatti ', 'aston martin ', 'mitsubishi ']
    randWord = random.choice(words)
    blanks = '_ ' * len(randWord)
    guessing(blanks, randWord)


def sectionTwo():
    words = ['gonorrhea ', 'nasopharyngeal carcinoma ', 'ependymoma ', 'tuberculosis ']
    randWord = random.choice(words)
    blanks = '_ ' * len(randWord)
    guessing(blanks, randWord)



def sectionThree():
    words = ['tardigrade ', 'komodo dragon ', 'bontebok ', 'ferruginous hawk ']
    randWord = random.choice(words)
    blanks = '_ ' * len(randWord)
    guessing(blanks, randWord)


def sectionFour():
    words = ['pythagorean ', 'differentiation ', 'polyhedron ', 'googolplex ']
    randWord = random.choice(words)
    blanks = '_ ' * len(randWord)
    guessing(blanks, randWord)


def guessing(blanks, randWord):
    missed = []
    print ()
    print ("Word: ",blanks)
    attempts = 15
    while attempts != 0:
        attempts = attempts - 1
        print ('Guess a letter, you have ' + str(attempts) + ' attempts left.')
        guessLetter = input()
        if guessLetter in randWord:
            newBlanks = " ".join(c if c in guessLetter else "_" for c in randWord)
            print ('Correct!')
            print ()
            print ("Word: ",newBlanks)
        else:
                  missed.append(guessLetter)
                  print ('That letter is not in the word, you have guessed the following letters:')
                  print (', '.join(missed))
                  print ()


playAgain = ''
while playAgain != 'yes' and playAgain!= 'no':
    intro()
    optionNumber = optionSelect()
    checkChoice(optionNumber)
    print('Do you want to play again? (yes or no)')
    #Play again or not
    playAgain = input()
    if playAgain == 'yes':
        played = 1
        playAgain =''
    else:
        print('Thanks for Playing! Bye!')
        time.sleep(2)
        quit()

Answer 1

问题是您没有存储 newBlanks，因此每次用户猜对字母时，程序都会重新创建字符串。因此，您需要跟踪猜对了哪些字母。您可以通过替换 if 语句中未重估的局部变量中的每个猜测字母来实现。您可以使用以下 while 循环解决此问题:

while attempts != 0:
    attempts = attempts - 1
    print ('Guess a letter, you have ' + str(attempts) + ' attempts left.')
    guessLetter = input()
    if guessLetter in randWord:
        newBlanks = " ".join(c if c in guessLetter else "_" for c in randWord)
        index = 0
        for letter in newBlanks:
            if letter != '_' and letter != ' ':
                blanks= blanks[:index] + letter + blanks[index+1:]
            index += 1
        print ('Correct!')
        print ()
        print ("Word: ",blanks)

ps，你的一些单词中有空格，你可能想确保空格不被视为猜测