c - 帮助!当输入 strtok 结果时，strcmp 在骗我

Question

strcmp，当输入 strtok 的结果时，下面的代码似乎在公然骗我。

int fSize;
char * buffer=NULL;
char * jobToken = "job";
char * nextToken=NULL;
job * curJob=NULL;
struct node * head=NULL;
struct node * parseList(FILE* file){
    fseek(file,0,SEEK_END);
    fSize=ftell(file);
    buffer = (char*)malloc(fSize+1);
    printf("%d chars: reading buffer now:\n",fSize);
    fseek(file,0,SEEK_SET);
    fread (buffer,1,fSize,file);
    nextToken = strtok(buffer, " \n");
    while (nextToken!=NULL){
            printf("**Running  Token: %s**\n",nextToken);
            if (strcmp(nextToken,jobToken)){
                    printf("Accepted %s  as %s\n",nextToken,jobToken);                
            }else{
                    printf("not %s, %s\n",jobToken,nextToken);
            }

            printf("End of state - %s\n",nextToken);

            nextToken = strtok(NULL, " \n");
    }
    free (buffer);
    return NULL;
}

在 parseList 参数的文件中输入此内容:

job 23
job 10

给出这个输出:

14 chars: reading buffer now:
**Running  Token: job**
not job, job
End of state - job
**Running  Token: 23**
Accepted 23  as job
End of state - 23
**Running  Token: job**
not job, job
End of state - job
**Running  Token: 10**
Accepted 10  as job
End of state - 10

谎言!

Answer 1

当您比较的字符串相等时，

strcmp 返回 0。您需要使用 if (!strcmp(...))。