c - 错误 : invalid operands to binary expression ('float' and 'float' )

Question

如果之前有人问过这个问题，我深表歉意。我环顾四周，找不到解决方案，我是 C 的新手。我知道我无法从 float 中获得 %。如果我使用 2 个 float ，我将如何捕获这个数学的剩余部分？

#include <cs50.h>
#include <stdio.h>
#include <ctype.h>
#include <math.h>

/*
** Always use the largest coin possible
** keep track of coins used
** Print the final amount of coins
*/

int main (void)
{
  float change;
  int counter = 0;
  int division;
  //float rem;
  float quarter = 0.25;
  //float quarter = 0.25, dime = 0.10, nickel = 0.05, penny = 0.01;
  /* Prompt user for an amont of change*/
  do{
    printf("How much do we owe you in change? ");
    change = GetFloat();
  }
  while (change <= 0);
  if (change >= quarter)
  {
    division  = (change / quarter);
    counter += division;
    //change = (int)(change % quarter);
    printf("change: %.2f\n", change);
    printf("counter: %d\n ", counter);
  }

  return (0);
}

Answer 1

你可能想检查一下 fmod .

您还可以执行类似change = change - (int)(change/quarter) * quarter