c - 如何读取实数输入并使用它们

Question

你好，我在编码方面经验很少，但我在学校解决的问题要求我有一个输入，例如“12.5 ”，并处理该输入以给我一定的输出。

我正在尝试修改这段代码来做到这一点，但没有成功

代码是C语言

例如，“rate”类似于“12.5”，但它只读取“12”，然后继续使用 12 进行计算，并忽略 .5

我需要它来阅读整个 12.5

感谢您提供的任何帮助。

#include <stdio.h>

int main ()
{
    int hours_2weeks;
    int rate;
    int Gross_Pay;
    int Social_security_tax;
    int Federal_tax;
    int State_tax;
    int Medical_dental;
    int Net_Pay;
    printf("\nPayroll Program for X Y Z Corp.\n");
    {
    printf("Enter hours worked: ");
    scanf("%d", &hours_2weeks);

    printf("Enter hourly rate: ");
    scanf("%d", &rate);
    }
    printf("This employee worked %d hours with a salary of $%d per hour. Here is the salary statement for this employee:\n",hours_2weeks,rate);

    Gross_Pay=hours_2weeks*rate;
    printf("Gross Pay: %d\n", Gross_Pay);
    Social_security_tax=hours_2weeks*rate*.06;
    printf("Social security tax: -%d\n", Social_security_tax);
    Federal_tax=hours_2weeks*rate*.1;
    printf("Federal tax: -%d\n", Federal_tax);
    State_tax=hours_2weeks*rate*.05;
    printf("State tax: -%d\n", State_tax);
    Medical_dental=hours_2weeks*rate*.05;
    printf("Medical/dental: -%d\n", Medical_dental);
    Net_Pay=hours_2weeks*rate-(hours_2weeks*rate*.06)-(hours_2weeks*rate*.1)-(hours_2weeks*rate*.05)-(hours_2weeks*rate*.05);
    printf("Net Pay: %d\n", Net_Pay);
}

Answer 1

您将所有输入变量定义为整数。即使您键入 double 值，系统也会将这些值转换/转换为整数...

你正在这样做:

 int hours_2weeks;
 printf("Enter hours worked: ");
 scanf("%d", &hours_2weeks);

改为:

double hours_2weeks;
printf("Enter hours worked: ");
scanf("%lf", &hours_2weeks);