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java - C 套接字服务器,Java 套接字客户端 : BLOCKING!

转载 作者:太空宇宙 更新时间:2023-11-04 00:22:46 25 4
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我将我的代码粘贴到一个简单的 C 套接字服务器和一个 Java 客户端。

我在 Java 中使用 write 方法逐字符发送。然而,在发送完字符 block (此处为“h”、“e”、“y”)后,Java 客户端被阻止发送,因为 C 服务器不回复它:(

我假设发送空字符(从 Java 写入)会在 C 端停止 recv 时存在一些问题。

如有任何帮助,我们将不胜感激。

C 服务器:

#include <stdio.h>   /* standard in and output*/
#include <sys/socket.h> /* for socket() and socket functions*/
#include <arpa/inet.h> /* for sockaddr_in and inet_ntoa() */
#include <stdlib.h>
#include <string.h>
#include <unistd.h> /* for close() */


int main(int argc, char *argv[]){
int sock, connected, bytes_received, true = 1;
char recv_data;
char replyBuffer[32];

struct sockaddr_in server_addr,client_addr;
int sin_size;
if ((sock = socket(AF_INET, SOCK_STREAM, 0)) == -1) {
perror("Socket");
exit(1);
}

if (setsockopt(sock,SOL_SOCKET,SO_REUSEADDR,&true,sizeof(int)) == -1) {
perror("Setsockopt");
exit(1);
}

server_addr.sin_family = AF_INET;
server_addr.sin_port = htons(2400);
server_addr.sin_addr.s_addr = INADDR_ANY;
bzero(&(server_addr.sin_zero),8);

if (bind(sock, (struct sockaddr *)&server_addr, sizeof(server_addr)) == -1) {
perror("Unable to bind");
exit(1);
}

if (listen(sock, 5) == -1) {
perror("Listen");
exit(1);
}

printf("\nTCPServer Waiting for client on port 2400");

while(1){
sin_size = sizeof(client_addr);
connected = accept(sock, (struct sockaddr *)&client_addr,&sin_size);
printf("\n Got a connection from (%s , %d)",inet_ntoa(client_addr.sin_addr),ntohs(client_addr.sin_port));


while ((bytes_received = recv(connected,&recv_data,1,0)) > 0){
printf("\nrecv= %c\n", recv_data);
}
int success = 1;
sprintf(replyBuffer, "%d", success);
printf("reply buffer = %s\n", replyBuffer);
if (send(connected, replyBuffer, strlen(replyBuffer), 0) == -1)
perror("send() failed");
success = 0;
close(connected);
}
}

Java 客户端:

import java.net.*;
import java.io.*;

public class Client1
{
public static void main(String[] args) throws IOException {
if (args.length < 2) {
System.err.println("Usage: java Client1 <IP address> <Port number>");
System.exit(0);
}
BufferedReader in = null;
OutputStream out = null;
Socket sock = null;

try {
sock = new Socket(args[0], Integer.parseInt(args[1]));
out = sock.getOutputStream();
in = new BufferedReader(new InputStreamReader(sock.getInputStream()));

String line = "hey";
String responseline = null;
char[] strArray;
strArray = line.toCharArray();

while (true) {
for( int index = 0; index < strArray.length; index++){
out.write(strArray[index]);
}
out.flush();
System.out.println("data sent " );
System.out.println("val returned"+in.readLine());
}
}
catch (IOException ioe) {
System.err.println(ioe);
}
finally {
if (in != null)
in.close();

if (out != null)
out.close();
if (sock != null)
sock.close();
}
}
}

最佳答案

来自 BufferedReader.readLine() 的 javadoc

Read a line of text. A line is considered to be terminated by any one of a line feed ('\n'), a carriage return ('\r'), or a carriage return followed immediately by a linefeed. 

这就是它阻塞的原因(没有 lf,没有 cr,没有 crlf)

[编辑]
您需要创建一个 C 程序可以理解的 EOL 指示器(就像 java 客户端中的 readLine() 一样。让该指示器为 '\n'(如果没有别的,为了保持一致性)
在 Client.java 中,将 '\n' 附加到您发送的字符串。
在 tst.c 中,测试 '\n',当它被接收时,从 recv() 循环中跳出
[/edit]

关于java - C 套接字服务器,Java 套接字客户端 : BLOCKING!,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4036040/

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