python - 如何在 python 中使用 cron 和 smtp 安排在特定时间发送电子邮件？

Question

到目前为止，我只能发送电子邮件。这是我的代码:

import smtplib

email_user = 'myemail@gmail.com'
server = smtplib.SMTP ('smtp.gmail.com', 587)
server.starttls()
server.login(email_user, 'email pass')

#SET TIME HERE?
from crontab import CronTab

#EMAIL
message = 'sending this from python!'
server.sendmail(email_user, email_user, message)
server.quit()

我正在努力设定发送电子邮件的时间。如果有人也能帮我弄清楚如何添加附件，那就太好了!

Answer 1

假设您的 send_email() 函数已经正常工作，我会这样做:

import datetime as dt
import time
import smtplib

def send_email():
    email_user = 'myemail@gmail.com'
    server = smtplib.SMTP ('smtp.gmail.com', 587)
    server.starttls()
    server.login(email_user, 'email pass')

    #EMAIL
    message = 'sending this from python!'
    server.sendmail(email_user, email_user, message)
    server.quit()

send_time = dt.datetime(2018,8,26,3,0,0) # set your sending time in UTC
time.sleep(send_time.timestamp() - time.time())
send_email()
print('email sent')

如果你想定期发送邮件，你可以这样做:

import datetime as dt
import time
import smtplib

def send_email():
    email_user = 'myemail@gmail.com'
    server = smtplib.SMTP ('smtp.gmail.com', 587)
    server.starttls()
    server.login(email_user, 'email pass')

    #EMAIL
    message = 'sending this from python!'
    server.sendmail(email_user, email_user, message)
    server.quit()

def send_email_at(send_time):
    time.sleep(send_time.timestamp() - time.time())
    send_email()
    print('email sent')

first_email_time = dt.datetime(2018,8,26,3,0,0) # set your sending time in UTC
interval = dt.timedelta(minutes=2*60) # set the interval for sending the email

send_time = first_email_time
while True:
    send_email_at(send_time)
    send_time = send_time + interval

您还可以生成一个线程并让该线程处理电子邮件的发送。