Python，打印出字典中每个可能组合的元素总和的键

Question

创建以下行以迭代和总结字典中每个可能的元素组合。例如，如果字典的长度是 5，我想要任意 2 个元素、任意 3 个元素、任意 4 个元素的总和。

import itertools

di = {'a': 1, 'b': 2, 'c': 34, 'd': 24}

dict_len = range(len(di)-2, len(di))

for l in dict_len:
    d_values = list(itertools.combinations(di.values(), l))
    for d in d_values:
        print d

输出:

35
3
25
36
58
26
37
59
27
60

我怎样才能同时打印出值的键？喜欢:

a + c = 35
a + b = 3
a + d = 25
b + c = 36
c + d = 58
b + d = 26
a + b + c =37
a + c + d =59
a + b + d =27
c + b + d =60

谢谢。

Answer 1

要获得所需的输出(如问题中所述):

import itertools

di = {'a': 1, 'b': 2, 'c': 34, 'd': 24}

dict_len = range(len(di)-2, len(di))

for l in dict_len:
    d_values = list(itertools.combinations(di.values(), l))
    d_keys = list(itertools.combinations(di.keys(), l))
    for i in range(len(d_values)):
        print " + ".join(d_keys[i]), "=", sum(d_values[i])

输出:

a + c = 35
a + b = 3
a + d = 25
c + b = 36
c + d = 58
b + d = 26
a + c + b = 37
a + c + d = 59
a + b + d = 27
c + b + d = 60