python - 如何获取当前周之前的年份和周数？

Question

我知道当前年份和当前周，例如当前年份是 2018，当前周是 8。

我想知道10周前是哪一年哪周，10周前是2017年的第五十周

currentYear=2018
currentWeek=8

如何获取？

Answer 1

In [31]: from datetime import datetime as dt

In [32]: from datetime import timedelta

In [33]: current_date = dt(2018, 2, 20)

In [34]: current_date
Out[34]: datetime.datetime(2018, 2, 20, 0, 0)

In [35]: current_date.strftime('%V') <-- This is how we can get week of year.
Out[35]: '08'

In [36]: current_date - timedelta(weeks=10) <-- How to go back in time.
Out[36]: datetime.datetime(2017, 12, 12, 0, 0)

In [37]: ten_weeks_ago = _

In [38]: ten_weeks_ago.strftime('%V')
Out[38]: '50'