python - 如何在 python 的给定文件路径中返回错误行？

Question

我希望 File1.py 返回 File2.py 中的错误行

File1.py:

def find_errors(file_path_of_File2):
    print(f'the error is on line {}')

the error is on line 2

文件2.py:

print('this is line 1')
print(5/0)

ZeroDivisionError: integer division or modulo by zero

这可能吗？

Answer 1

你可以用 traceback module 做的有点难看.

File1.py

print('this is line 1')
print(5/0)

File2.py

import sys
import traceback
try:
    import test
except Exception as e:
    (exc_type, exc_value, exc_traceback) = sys.exc_info()
    trace_back = [traceback.extract_tb(sys.exc_info()[2])[-1]][0]
    print("Exception {} is on line {}".format(exc_type, trace_back[1]))

输出

this is line 1
Exception <type 'exceptions.ZeroDivisionError'> is on line 2

在这种情况下，您将捕获在导入文件期间引发的所有异常，然后您将从 trace_back 中获取最后一个异常。