c - 如何从c中的文件中读取特定值

Question

如果我有包含学生分数的文件例如这个文件

{ 
students scores :
100
90
83
70
}

如何在不读取“学生分数:”的情况下只读取分数的值？？？

mu代码已经ok了但是读取值的问题

这是我的代码

#include <stdio.h>

int main (void)
{
    FILE *infile;
    double score, sum=0, average;
    int count=0, input_status;

    infile = fopen("scores.txt", "r");
    input_status = fscanf(infile, "%lf", &score);
    while (input_status != EOF) 
    {
        printf("%.2f\n ", score);
        sum += score;
        count++;
        input_status = fscanf(infile, "%lf",  &score);
    }
    average = sum / count;

    printf("\nSum of the scores is %f\n", sum);
    printf("Average score is %.2f\n", average);
    fclose(infile);
    getch();
}

Answer 1

我看到的问题:

input_status = fscanf(infile, "%lf", &score);
while (input_status != EOF) 

是不对的。如果读取不成功，fscanf 的返回值将为 0，如果读取成功，则为 1。

更重要的是，您需要添加代码来跳过所有内容，直到您希望看到数字为止。

char line[100];
while ( fgets(line, 100, infile) != NULL )
{
  // If the line containing "students scores :"
  // is found, break from the while loop.
  if (strstr(line, "students scores :") != NULL )
  {
    break;
  }
}

然后，将读取数据的行的开头更改为:

input_status = fscanf(infile, "%lf", &score);
while (input_status == 1 )