python - pop() 函数没有完全弹出列表中位数

Question

问题描述:

un_confirmusers = ['A','B','C','D','E']
confirmusers = []
for un_confirmuser in un_confirmusers:
    current_user = un_confirmusers.pop()
    print("The current USER is: " + current_user.title())
    confirmusers.append(current_user)
print(confirmusers)
print(un_confirmusers)

编译结果:

The current USER is： E
The current USER is： D
The current USER is： C
['E', 'D', 'C']
['A', 'B']

我不知道 pop() 没有完全弹出列表中位数。谢谢。

Answer 1

您可以使用 while 循环 而不是使用 for 循环

例如:

un_confirmusers = ['A','B','C','D','E']
confirmusers = []
while un_confirmusers:                      #!Update.
    current_user = un_confirmusers.pop()
    print("The current USER is: " + current_user.title())
    confirmusers.append(current_user)
print(confirmusers)
print(un_confirmusers)

输出:

The current USER is: E
The current USER is: D
The current USER is: C
The current USER is: B
The current USER is: A
['E', 'D', 'C', 'B', 'A']
[]

注意:在遍历对象时移除元素不是一个好习惯。