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node.js - Mongoose 获取与条件的关系计数

转载 作者:太空宇宙 更新时间:2023-11-03 23:56:30 25 4
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我有两个架构

车辆架构:

const VehicleSchema = new Schema({
title: {
type: String,
required: true
},
price: {
type: Number,
required: true
},
);
VehicleSchema.virtual('booking', {
ref: 'Booking',
localField: '_id',
foreignField: 'vehicle',
options: {sort: {created_at: 1}}
});
export default mongoose.model('Vehicle', VehicleSchema);

预订架构:

const BookingSchema = new Schema({
start_at:{
type:Date,
required:true
},
end_at:{
type:Date,
required:true
},
status: {
type: String,
enum: ["APPROVED", "REJECTED",],
default: "REJECTED"
},
vehicle:{
type: Schema.Types.ObjectId,
ref: 'Vehicle'
},
});
export default mongoose.model('Booking', BookingSchema);

每辆车辆都有多个预订

我需要获取所有状态为拒绝批准状态的车辆:

 [
{
"title":"vehicle_1",
"price":2500,
"rejected_count":10
"approved_count":55
},{
"title":"vehicle_2",
"price":2500,
"rejected_count":15
"approved_count":5
},{
"title":"vehicle_3",
"price":2500,
"rejected_count":1
"approved_count":30
},{
"title":"vehicle_4",
"price":2500,
"rejected_count":5
"approved_count":15
},
]

最佳答案

您可以使用以下聚合

Vehicle.aggregate([
{ "$lookup": {
"from": Booking.collection.name,
"let": { "vehicle": "$_id" },
"pipeline": [
{ "$match": {
"$expr": { "$eq": [ "$vehicle", "$$vehicle" ] },
"status": "APPROVED"
}}
],
"as": "approved"
}},
{ "$lookup": {
"from": Booking.collection.name,
"let": { "vehicle": "$_id" },
"pipeline": [
{ "$match": {
"$expr": { "$eq": [ "$vehicle", "$$vehicle" ] },
"status": "REJECTED"
}}
],
"as": "rejected"
}},
{ "$project": {
"rejected_count": { "$size": "$rejected" },
"approved_count": { "$size": "$approved" },
"title": 1,
"price": 1
}}
])

关于node.js - Mongoose 获取与条件的关系计数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56875898/

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