python - 程序在套接字交互期间挂起

Question

我有两个程序，sendfile.py 和 recvfile.py，它们应该交互以通过网络发送文件。它们通过 TCP 套接字进行通信。通信应该是这样的:

sender =====filename=====> receiver

sender <===== 'ok' ======= receiver
               or
sender <===== 'no' ======= receiver

if ok:
sender ====== file ======> receiver 

我有

发件人和收件人代码在这里:

发件人:

import sys
from jmm_sockets import *

if len(sys.argv) != 4:
    print "Usage:", sys.argv[0], "<host> <port> <filename>"
    sys.exit(1)

s = getClientSocket(sys.argv[1], int(sys.argv[2]))

try:
    f = open(sys.argv[3])
except IOError, msg:
    print "couldn't open file"
    sys.exit(1)

# send filename
s.send(sys.argv[3])

# receive 'ok'
buffer = None
response = str()
while 1:
    buffer = s.recv(1)
    if buffer == '':
        break
    else:
        response = response + buffer
if response == 'ok':
    print 'receiver acknowledged receipt of filename'
    # send file
    s.send(f.read())
elif response == 'no':
    print "receiver doesn't want the file"

# cleanup
f.close()
s.close()

接收者:

from jmm_sockets import *

s = getServerSocket(None, 16001)
conn, addr = s.accept()


buffer = None
filename = str()

# receive filename
while 1:
    buffer = conn.recv(1)
    if buffer == '':
        break
    else:
        filename = filename + buffer
print "sender wants to send", filename, "is that ok?"
user_choice = raw_input("ok/no: ")

if user_choice == 'ok':
    # send ok
    conn.send('ok')
    #receive file
    data = str()
    while 1:
        buffer = conn.recv(1)
        if buffer=='':
            break
        else:
            data = data + buffer
            print data
else:
    conn.send('no')
conn.close()

我确定我在某种僵局中遗漏了一些东西，但不知道它是什么。

Answer 1

使用阻塞套接字，这是默认的，我假设是你正在使用的(不能确定，因为你正在使用一个神秘的模块 jmm_sockets)，recv 方法是阻塞的——当它“暂时没有更多可返回的”时，它不会返回空字符串，正如您所假设的那样。

您可以解决这个问题，例如，通过发送一个明确的终止符(绝不能出现在文件名中)，例如'\xff'，在您要发送的实际字符串之后，并在另一端等待它作为现在已收到所有字符串的指示。