javascript - Sequelize : user. checkPassword 不是函数

Question

我正在尝试在sequelize模型中创建一个原型(prototype)函数，以验证我的密码:

const bcrypt = require('bcryptjs');

module.exports = (sequelize, DataTypes) => {
  const User = sequelize.define(
    'User',
    {
      name: DataTypes.STRING,
      email: DataTypes.STRING,
      password: DataTypes.VIRTUAL,
      password_hash: DataTypes.STRING
    },
    {
      hooks: {
        beforeSave: async user => {
          if (user.password) {
            user.password_hash = await bcrypt.hash(user.password, 8);
          }
        }
      }
    }
  );

  **User.prototype.checkPassword = function(password) {
    debugger
    return bcrypt.compare(password, this.password_hash);
  };**

  return User;
};

但是当我将此模型导出到 Controller 并尝试调用 user.checkpassword 时，它给出了 TypeError: user.checkPassword is not a function:

const { User } = require('../models');

class SessionController {
  async store(req, res) {
    const { email, password } = req.body;
    const user = User.findOne({ where: { email } });

    if (!user) {
      return res.status(401).json({ message: 'User not found' });
    }

    **if (!(await user.checkPassword(password))) {
      return res.status(401).json({ message: 'Incorret password' });
    }**

    return res.status(200).send();
  }
}

module.exports = new SessionController();

这会是什么？

我的 Sequelize 版本是“sequelize”:“^5.21.5”

Answer 1

User.findOne({ where: { email } });

返回一个 promise 。你可能打算这样做

const user = await User.findOne({ where: { email } });

而不是

const user = User.findOne({ where: { email } });