c# - 显示随机网格 c#

Question

我在 Windows Phone 中随机显示一些网格时遇到问题。我创建了自己的代码，它工作正常但并不简单。也许有一种更简单的方法可以在 Windows Phone 中显示随机网格。

这是我的应用所需要的:

我想点击一个按钮来显示随机网格。当我再次点击时，它应该显示另一个网格并隐藏之前的网格。它现在应该显示任何网格两次。

这是我自己的代码:

List<int> number = new List<int> { 1,2,3,4,5 }; //create list
private void Button_Click_2(object sender, RoutedEventArgs e)
{
    int numberrandom;
    Random bsd = new Random();
    if (number.Count > 0) // get random number from (numberlist) without repetition
    {
        int fIndex = bsd.Next(0, number.Count); 

        numberrandom = number[fIndex]; 
        txtbox1.Text = numberrandom.ToString(); // show random number at txtbox
        number.RemoveAt(fIndex);            
    }
    else 
    {
        messagebox.show("no more grid show");
    }

    int a = Convert.ToInt32(txtbox1.Text); // convert number txtbox from string to int
    int val = a;
    switch (val)
    {
        case 1: //show grid 1
            grid1.Visibility = Visibility.Visible; 
            grid2.Visibility = Visibility.Collapsed;
            grid3.Visibility = Visibility.Collapsed;
            grid4.Visibility = Visibility.Collapsed;
            grid5.Visibility = Visibility.Collapsed;
        break;
        case 2: //show grid 2
            grid1.Visibility = Visibility.Collapsed;
            grid2.Visibility = Visibility.Visible;
            grid3.Visibility = Visibility.Collapsed;
            grid4.Visibility = Visibility.Collapsed;
            grid5.Visibility = Visibility.Collapsed;
            break;
        case 3: //show grid 3
            grid1.Visibility = Visibility.Collapsed;
            grid2.Visibility = Visibility.Collapsed;
            grid3.Visibility = Visibility.Visible;
            grid4.Visibility = Visibility.Collapsed;
            grid5.Visibility = Visibility.Collapsed;
        break;
        case 4: //show grid 4
            grid1.Visibility = Visibility.Collapsed;
            grid2.Visibility = Visibility.Collapsed;
            grid3.Visibility = Visibility.Collapsed;
            grid4.Visibility = Visibility.Visible;
            grid5.Visibility = Visibility.Collapsed;
        break;
        case 5: //show grid 5
            grid1.Visibility = Visibility.Collapsed;
            grid2.Visibility = Visibility.Collapsed;
            grid3.Visibility = Visibility.Collapsed;
            grid4.Visibility = Visibility.Collapsed;
            grid5.Visibility = Visibility.Visible;
        break;
    }

Answer 1

您可以进行一些改进:

List<Grid> grids = new List<Grid> { grid1, grid2, grid3, gridN ... };
int gridIndex = 0;

void Load() {
    grids.Shuffle(); // use the extension method linked below
}

void Button_Click_2(object sender, RoutedEventArgs e) {
    if (gridIndex >= grids.Count)
        return;

    if (gridIndex > 0) {
        grids[gridIndex - 1].Visibility = Visibility.Collapsed;
    }
    grids[gridIndex].Visibility = Visibility.Visible;
    gridIndex++;
}

需要显示原来的格子号吗？如果没有，上面的代码就简单多了。这是 Shuffle() 扩展方法，我从 this answer 得到它:

public static void Shuffle<T>(this IList<T> list)  
{  
    Random rng = new Random();  
    int n = list.Count;  
    while (n > 1) {  
        n--;  
        int k = rng.Next(n + 1);  
        T value = list[k];  
        list[k] = list[n];  
        list[n] = value;  
    }  
}