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c - 如何使用 C 从 .txt 文件中读取最后 3 个变量值

转载 作者:太空宇宙 更新时间:2023-11-03 23:43:38 24 4
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我的 C 语言编程经验有限,但由于软件限制,我不得不使用这种语言。我正在尝试为 CFD 软件编写用户自定义。

软件在计算过程中写入一个输出文件,我想监控变量“PERCENT FILLED”,当数值稳定时终止模拟。我可以终止代码,我遇到的问题是使用 C 读取 PERCENT FILLED 的值,我可以在 python 或 shell 脚本中轻松执行此操作,但我真的很难使用 C。

可能有更优雅的方法来实现这一点,我很乐意学习,但我不是经验丰富的程序员,所以我可能会迷失在复杂的解决方案中。

我试图通过将任务分解成更小的子任务来做到这一点。代码的效率并不重要,因为这个函数不必经常运行并且要读取的文件不是很大。我相信有更快更优雅的方法可以做到这一点!使用网络上的其他代码并修改它们,我想出了以下内容。

我尝试完成以下子任务:A)删除所有包含“PERCENT FILLED”的行并将它们写入文件(PERCENT FILLED.txt)B) 读取此文件中的行数,然后将最后 3 行读取到单独的变量中。C) 然后我需要重新格式化这些变量。例如,将 3 个变量从“PERCENT FILLED = 6.72902E+00”形式的字符串更改为浮点值,例如 6.72902。

我已经完成了 A),B) 有错误,并且不知道从哪里开始 C)。

B) 中的错误 - 当我运行代码时,它在 while 循环中正确地为 line1、line2 和 line3 分配了值,但是一旦在 while 循环之外,所有值都会更改为 line1 的值。这个我不明白。任何人都可以帮助我理解和解决这个问题吗?

示例代码输出:

line3: PERCENT FILLED =   6.31275E+00
line2: PERCENT FILLED = 6.50146E+00
line1: PERCENT FILLED = 6.72902E+00
******************
out line1: PERCENT FILLED = 6.72902E+00
out line2: PERCENT FILLED = 6.72902E+00
out line3: PERCENT FILLED = 6.72902E+00

C) 部分 - 我不知道从哪里开始。看起来有足够的内联信息可以使用 atof() 将字符串转换为 float 。但是,我首先需要从字符串的开头删除 PERCENT FILLED =,然后转换工程编号格式(某些值为 1.00E+02,因此简单地删除最后 4 个字符 - E+00 - 将不起作用)。我不知道该怎么做。任何帮助,将不胜感激。

示例输入文件(通过删除 PERCENT FILLED 值之间的可能行简化):

  Step = 171 Iteration = 0 Time step = 0.014849 Time = 4.834002
Iter Variable Solver Loops Delta Solve CPU Form CPU
0 F EXPLC 4 1.0000000E+00 0.007999 0.000000
FRACTION SOLID = 0.000000e+00 %
PERCENT FILLED = 5.46882E+00
Step = 172 Iteration = 0 Time step = 0.029698 Time = 4.863700
Iter Variable Solver Loops Delta Solve CPU Form CPU
0 F EXPLC 11 1.0000000E+00 0.018997 0.000000
FRACTION SOLID = 0.000000e+00 %
PERCENT FILLED = 5.70902E+00
Step = 173 Iteration = 0 Time step = 0.029698 Time = 4.893398
Time step reduced by COURANT limit in free_surface, c_lim = 2.032750e-02
Iter Variable Solver Loops Delta Solve CPU Form CPU
0 F EXPLC 6 1.0000000E+00 0.010998 0.000000
FRACTION SOLID = 0.000000e+00 %
PERCENT FILLED = 5.89665E+00
Step = 174 Iteration = 0 Time step = 0.020328 Time = 4.904356
Iter Variable Solver Loops Delta Solve CPU Form CPU
0 F EXPLC 7 1.0000000E+00 0.011997 0.000000
FRACTION SOLID = 0.000000e+00 %
PERCENT FILLED = 6.08026E+00
Step = 175 Iteration = 0 Time step = 0.040655 Time = 4.945011
Time step reduced by COURANT limit in free_surface, c_lim = 2.547617e-02
Iter Variable Solver Loops Delta Solve CPU Form CPU
0 F EXPLC 9 1.0000000E+00 0.016998 0.000000
FRACTION SOLID = 0.000000e+00 %
PERCENT FILLED = 6.31275E+00
Step = 176 Iteration = 0 Time step = 0.025476 Time = 4.955307
Time step reduced by COURANT limit in free_surface, c_lim = 1.997734e-02
Iter Variable Solver Loops Delta Solve CPU Form CPU
0 F EXPLC 9 1.0000000E+00 0.016994 0.000000
FRACTION SOLID = 0.000000e+00 %
PERCENT FILLED = 6.50146E+00
Step = 177 Iteration = 0 Time step = 0.039955 Time = 4.989764
Time step reduced by COURANT limit in free_surface, c_lim = 2.547537e-02
Iter Variable Solver Loops Delta Solve CPU Form CPU
0 F EXPLC 13 1.0000000E+00 0.024994 0.000000
FRACTION SOLID = 0.000000e+00 %
PERCENT FILLED = 6.72902E+00

我当前的代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
char line[1000];
char *pch;
char c[] = "PERCENT FILLED =";
char buff[1000];


/* Create a list of PERCENT FILLED values and write to file - copy every line containing PERCENT FILLED from p.out file*/
FILE *fp = fopen("inputFILE.txt", "r");
FILE *op = fopen("PERCENT_FILLED.txt", "w");

if(fp == NULL || op == NULL)
{
fprintf(stderr, "Error opening file.");
exit(1);
}
else
{
while (fgets(line, sizeof(line), fp) != 0)
{
if((pch = strstr (line, c))!= 0)
fprintf(op, "%s", line);
}
}

fclose(fp);
fclose(op);


/* Get the total number of lines in the file PERCENT_FILLED.txt */

FILE* myfile = fopen("PERCENT_FILLED.txt", "r");
int ch, number_of_lines = 0;
int line_num = 0;
int count = 0;
char readline[256]; /* or other suitable maximum line size */
char* line1;
char* line2;
char* line3;

do
{
ch = fgetc(myfile);
if(ch == '\n')
number_of_lines++;
} while (ch != EOF);

// last line doesn't end with a new line!
// but there has to be a line at least before the last line
if(ch != '\n' && number_of_lines != 0)
number_of_lines++;

fclose(myfile);




/* Get the last 3 PERCENT_FILLED values from the PERCENT_FILLED.txt */


FILE* infile = fopen("PERCENT_FILLED.txt", "r");

if ( infile != NULL )
{
while (fgets(readline, sizeof line, infile) != NULL) /* read a line */
{
if (count == (number_of_lines-4))
{
line3 = readline;
count++;
printf("\nline3:%s", line3);
}
else if (count == (number_of_lines-3))
{
line2 = readline;
count++;
printf("line2:%s", line2);
}
else if (count == (number_of_lines-2))
{
line1 = readline;
count++;
printf("line1:%s", line1);
}
else
{
count++;
printf("readline:%s count:%d\n", readline, count);
}
}
fclose(infile);
}
printf("******************\n");
printf("out line1:%s", line1);
printf("out line2:%s", line2);
printf("out line3:%s\n\n", line3);


/* strip "PERCENT FILLED = " from the string and turn the string into a float */
/* Do this for line1, line2, line3 */
/* Example string is " PERCENT FILLED = 6.72902E+00" need to turn this in to a float variable of value 6.72902 */

return 0;

}

最佳答案

感谢您的帮助,我的代码现在可以正常工作,如下所示。我确信有一种更优雅的方法可以做到这一点,但为了完整起见,我将提供我的最终代码,以防它可以帮助别人。

    #include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
char line[1000];
char *pch;
char c[] = "PERCENT FILLED =";
char buff[1000];


/* Create a list of PERCENT FILLED values and write to file - copy every line containing PERCENT FILLED from p.out file*/
FILE *fp = fopen("inputFILE.txt", "r");
FILE *op = fopen("PERCENT_FILLED.txt", "w");

if(fp == NULL || op == NULL)
{
fprintf(stderr, "Error opening file.");
exit(1);
}
else
{
while (fgets(line, sizeof(line), fp) != 0)
{
if((pch = strstr (line, c))!= 0)
fprintf(op, "%s", line);
}
}

fclose(fp);
fclose(op);


/* Get the total number of lines in the file PERCENT_FILLED.txt */

FILE* myfile = fopen("PERCENT_FILLED.txt", "r");
int ch, number_of_lines = 0;
int line_num = 0;
int count = 0;
char readline[256]; /* or other suitable maximum line size */
char line1[256];
char line2[256];
char line3[256];

do
{
ch = fgetc(myfile);
if(ch == '\n')
number_of_lines++;
} while (ch != EOF);

// last line doesn't end with a new line!
// but there has to be a line at least before the last line
if(ch != '\n' && number_of_lines != 0)
number_of_lines++;

fclose(myfile);




/* Get the last 3 PERCENT_FILLED values from the PERCENT_FILLED.txt */


FILE* infile = fopen("PERCENT_FILLED.txt", "r");

if ( infile != NULL )
{
while (fgets(readline, sizeof line, infile) != NULL) /* read a line */
{
if (count == (number_of_lines-4))
{
strcpy ( line3, readline);
count++;
}
else if (count == (number_of_lines-3))
{
strcpy ( line2, readline);
count++;
}
else if (count == (number_of_lines-2))
{
strcpy ( line1, readline);
count++;
}
else
{
count++;
}
}
fclose(infile);
}

/* strip "PERCENT FILLED = " from the string and turn the string into a float */
/* Do this for line1, line2, line3 */
/* Example string is " PERCENT FILLED = 6.72902E+00" need to turn this in to a float varaible of value 6.72902 */

char per1[7], fil1[6], eq1[1];
char per2[7], fil2[6], eq2[1];
char per3[7], fil3[6], eq3[1];
float value1, value2, value3;

sscanf (line1, "%s %s %s %E", per1, fil1, eq1, &value1 );
sscanf (line2, "%s %s %s %E", per2, fil2, eq2, &value2 );
sscanf (line3, "%s %s %s %E", per3, fil3, eq3, &value3 );

printf("Value1: %f\n", value1 );
printf("Value2: %f\n", value2 );
printf("Value3: %f\n", value3 );


return 0;

}

关于c - 如何使用 C 从 .txt 文件中读取最后 3 个变量值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39498118/

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