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c - 错误地更新位字段

转载 作者:太空宇宙 更新时间:2023-11-03 23:42:10 25 4
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我正在尝试解决一个问题。它说,

Initialize a new variable to the value 17512807u.

Assume we number the bits as usual from 0 as least significant (on the right) to 31 (most significant, on the left). Update bits 18 through 21 with the integer value 8 and bits 10 through 14 with value 17 (decimal). Print the resulting value as an eight digit hexadecimal number to show all of the digits.

这是我想出的代码:

#include <stdio.h>

int main(){
int value = 17512807u;
int L = 21; // starting left position
int R = 18; // starting right position

int mask = (1 << (L - R + 1) - 1) << R;
int newField = (8 << R) & mask; // integer value 8, shifting to right
int newValue = value & (~mask); // remove range of bits
value = newField | newValue; // update range of bits

L = 14;
R = 10;

mask = (1 << (L - R + 1) - 1) << R;
newField = (17 << R) & mask;
newValue = value & (~mask);
value = newField | newValue;

printf("%08x\n", value);
}

我得到的答案是012b7d67

但是,有人告诉我这是错误的答案。我不知道正确答案是什么。

最佳答案

int mask = ((1 << (L - R + 1)) - 1) << R;

关于c - 错误地更新位字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42259429/

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